The problem asks for the average speed of a bus over its entire journey. Average speed is calculated by dividing the total distance traveled by the total time taken.
The bus travels in two parts:
Total distance = Distance (part 1) + Distance (part 2)
Total distance = 50 km + 70 km = 120 km
The time taken for each part is:
Total time = Time (part 1) + Time (part 2)
Total time = 95 min + 85 min = 180 minutes
Since the desired speed unit is km/h, we need to convert the total time from minutes to hours.
Total time in hours = \(\frac{180 \text{ min}}{60 \text{ min/hour}}\) = 3 hours
The formula for average speed is:
Average Speed = \(\frac{\text{Total Distance}}{\text{Total Time}}\)
Using the calculated values:
Average Speed = \(\frac{120 \text{ km}}{3 \text{ hours}}\)
Average Speed = 40 km/h
The average speed of the bus is 40 km/h.
A car runs first 275 km at an average speed of 50 km/h and the next 315 km at an average speed of 70 km/h. What is the average speed ( in km/h) for the entire journey?
Akhil rides first 12 km at a speed of 16 km/h and further 6 km at a speed of 20 km/h. Find his average speed (in km/h).
Shyam drives his car 30 km at a speed of 45 km/h and, for the next 1 h 20 m, he drives it at a speed of 51 km/h. Find his average speed (in km/h) for the entire journey.
X and Y travel a distance of 90 km each such that the speed of Y is greater than that of X. The sum of their speeds is 100 km/h and the total time taken by both is 3 hours 45 minutes. The ratio of the speed of X to that of Y is:
If a man travels at \(\frac{1}{x}\) km/h on a journey and returns at \(\rm \frac{1}{x^2}\) km/h, then his average speed for the journey is: