A circle with a radius of 10 cm, and a chord makes a 60° angle at the center. What is the length of that chord?
10 cm
Chord length = \(2r \sin(\theta/2)\), where r = 10 cm and θ = 60°. So chord length = \(2 \times 10 \times \sin 30° = 2 \times 10 \times 0.5 = 10 cm\).
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Important Questions from Circles, Chords and Tangents
In a circle, a ten cm long chord is at a distance of 12 cm from the centre of the circle. The length of the diameter of the circle (in cm) is:
Chord AB of a circle of radius 10 cm is at a distance 8 cm from the centre O. If tangents drawn at A and B intersect at P., then the length of the tangent AP (in cm) is:
A chord 21 cm long is drawn in a circle of diameter 25 cm. The perpendicular distance of the chord from the centre is:
In a circle with radius 5 cm, a chord is at a distance of 3 cm from the centre. The length of the chord is:
O is the centre of this circle. Tangent drawn from a point P, touches the circle at Q. If PQ = 24 cm and OQ = 10 cm, then what is the value of OP?
