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Question

Consider the following for the next ten (10) items that follow :
Each item contains a Question followed by two Statements. Answer each item using the following instructions :
Choose option
(a) If the Question can be answered by one of the Statements alone, but not by the other.
(b) If the Question can be answered by either Statement alone.
(c) If the Question can be answered by using both the Statements together, but cannot be answered by using either Statement alone.
(d) If the Question cannot be answered even by using both Statements together.

A circle touches all the four sides AB, BC, CD, DA of a quadrilateral ABCD.
Question : What is the perimeter of the quadrilateral?
Statement-I: \(AB + DC = 10\) cm
Statement-II: \(AD + BC = 10\) cm

This question was previously asked in
CDS 2 2024 Maths Question Paper (01-Sep-2024)
The correct answer is
c

Analyzing the Tangential Quadrilateral Properties

The problem involves a quadrilateral \(ABCD\) where a circle touches all its four sides (\(AB\), \(BC\), \(CD\), \(DA\)). Such a quadrilateral is called a tangential quadrilateral.

A key property of a tangential quadrilateral is that the sums of its opposite sides are equal.

For quadrilateral \(ABCD\), this property means:

\(AB + CD = AD + BC\)

The question asks for the perimeter of the quadrilateral. The perimeter (\(P\)) is the sum of all its sides:

\(P = AB + BC + CD + DA\)

We can rewrite the perimeter formula using the sums of opposite sides:

\(P = (AB + CD) + (AD + BC)\)

Evaluating Statement-I

Statement-I states that \(AB + DC = 10\) cm.

Because \(ABCD\) is a tangential quadrilateral, we know that the sum of opposite sides are equal:

\(AB + CD = AD + BC\)

Using Statement-I, we know one pair of opposite sides sums to 10 cm:

\(AB + CD = 10 \text{ cm}\)

Therefore, due to the property of tangential quadrilaterals, the other pair of opposite sides must also sum to 10 cm:

\(AD + BC = 10 \text{ cm}\)

However, Statement-I alone only provides the sum for one pair of opposite sides (\(AB + CD\)). To find the perimeter, we need the sum of *both* pairs, which is \((AB + CD) + (AD + BC)\). While we know \(AB + CD = 10\), we deduced \(AD + BC = 10\) using the tangential property, but the statement itself doesn't directly provide the sum needed for the second half of the perimeter calculation independently.

Thus, Statement-I alone is not sufficient to determine the perimeter.

Evaluating Statement-II

Statement-II states that \(AD + BC = 10\) cm.

Again, because \(ABCD\) is a tangential quadrilateral:

\(AB + CD = AD + BC\)

Using Statement-II, we know one pair of opposite sides sums to 10 cm:

\(AD + BC = 10 \text{ cm}\)

Therefore, the other pair of opposite sides must also sum to 10 cm:

\(AB + CD = 10 \text{ cm}\)

Similar to the analysis of Statement-I, Statement-II alone only gives the sum for one pair of opposite sides (\(AD + BC\)). The perimeter requires the sum of both pairs. While we know \(AD + BC = 10\), we deduced \(AB + CD = 10\) using the tangential property. The statement itself doesn't directly provide the sum needed for the first half of the perimeter calculation independently.

Thus, Statement-II alone is not sufficient to determine the perimeter.

Evaluating Both Statements Together

Let's consider both statements together:

  • Statement-I: \(AB + DC = 10\) cm
  • Statement-II: \(AD + BC = 10\) cm

Since the quadrilateral is tangential, we know that \(AB + CD = AD + BC\).

Statement-I tells us \(AB + CD = 10\) cm.

Statement-II tells us \(AD + BC = 10\) cm.

These two statements are consistent with the property of tangential quadrilaterals.

Now, let's calculate the perimeter \(P\) using both statements:

\(P = (AB + CD) + (AD + BC)\)

Substituting the values from Statement-I and Statement-II:

\(P = (10 \text{ cm}) + (10 \text{ cm})\) \(P = 20 \text{ cm}\)

Therefore, by using both statements together, we can successfully determine the perimeter of the quadrilateral.

Conclusion

The question "What is the perimeter of the quadrilateral?" can be answered using both Statement-I and Statement-II together, but neither statement alone is sufficient.

This corresponds to option (c).

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