A, B and C are three mutually exclusive and exhaustive events. P(A) = 2P(B) = 6P(C). Find P(B).
0.3
Let P(A) = 2x, P(B) = x, P(C) = x/3. Since A, B, and C are mutually exclusive and exhaustive events, P(A) + P(B) + P(C) = 1. 2x + x + x/3 = 1 10x/3 = 1 x = 3/10 = 0.3 P(B) = x = 0.3
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