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Question

A and B together have Rs. 6300. If 5/19 of A’s amount is equal to 2/5 of B’s amount, find the amount of B?

This question was previously asked in
SSC CGL 2016 (Tier 1) Previous Year Question Paper (11-Sep-2016) (Shift 2)
The correct answer is

Rs. 2500

Let A's amount be x and B's amount be y. According to the problem, x + y = 6300. We are also given that \(\frac{5}{19}\) of A's amount is equal to \(\frac{2}{5}\) of B's amount. This can be represented as:

\(\frac{5}{19}x = \frac{2}{5}y\)

To eliminate the fractions, multiply both sides by 95 (the LCM of 19 and 5):

5x = 38y

Express x in terms of y:

x = \(\frac{38}{5}y\)

Substitute this expression into the equation x + y = 6300:

\(\frac{38}{5}y + y = 6300\)

This simplifies to:

\(\frac{38y + 5y}{5} = 6300\)

\(\frac{43y}{5} = 6300\)

Multiply both sides by 5 to clear the fraction:

43y = 31500

Solving for y gives:

y = \(\frac{31500}{43}\)

Calculating the division gives:

y = 2500

Therefore, the amount of B is Rs. 2500.

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