$\frac{15}{1}$
To find the hourly wage, divide the total earnings by the number of hours worked.
Formula: Hourly Wage = Total Earnings / Hours Worked
Hourly Wage = $52.50 / 3.5$
Convert the earnings and hours into fractions:
Divide the earnings fraction by the hours fraction:
Hourly Wage = $\frac{105}{2} \div \frac{7}{2}$
To divide fractions, multiply by the reciprocal of the divisor:
Hourly Wage = $\frac{105}{2} \times \frac{2}{7}$
Multiply the numerators together and the denominators together:
Hourly Wage = $\frac{105 \times 2}{2 \times 7} = \frac{210}{14}$
Simplify the fraction:
Hourly Wage = $\frac{105}{7}$
Perform the division:
Hourly Wage = $15$
The question asks for the hourly wage as a fraction. Express $15$ as a fraction:
Hourly Wage = $\frac{15}{1}$
This matches Option 1.
Which fraction among the following is the least ?
\(\frac{5}{11}, \frac{7}{12}, \frac{8}{13}, \frac{9}{17}\)
Find the value of the following expression:
\(\frac{{3 \div 1 \times 2 + 5 - 2}}{{3 \times 3 - 2}}\)
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
If the sum of two positive numbers is 65 and the square root of their product is 26, then the sum of their reciprocals is:
The value of \(9 \div [\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}\div(\frac{3}{4}-\frac{1}{3})\;of\;\frac{2}{9}]\) is: