To solve this problem, we need to systematically try interchanging the signs and numbers provided in the options to see which combination results in a value of zero.

Let's analyze the given expression: \(2 - 55 + 11 \times 4 \div 18\)

Option 1: Interchanging ‘=‘ and ‘+’ and ‘11’ and ‘1’ results in \(2 - 55 + 1 \times 4 \div 18 = 2 - 55 + 4/18 \approx -52.77\). This is not zero.

Option 2: Interchanging ‘x’ and ‘-’ and ‘4’ and ‘11’ results in \(2 - 55 + 11 \times 4 \div 18 = 2 - 55 + 11 \div 4 \times 18 = 2-55+49.5 = -2.5\). This is not zero.

Option 3: Interchanging ‘-’ and ‘+’ and ‘2’ and ‘4’ results in \(4 - 55 + 2 \times 11 \div 18 = 4 - 55 + 22/18 \approx -46.88\). This is not zero.

Option 4: Interchanging ‘=‘ and ‘+’ and ‘2’ and ‘18’ results in \(18 - 55 + 11 \times 4 \div 2 = 18 - 55 + 22 = -15\). This also does not equal zero. There seems to be an error in the provided options. Let's re-evaluate the problem by substituting the signs and numbers according to Option 4: \(18 - 55 + 11 × 4 ÷ 2\).

Following the order of operations (PEMDAS/BODMAS), we calculate: \(11 × 4 = 44\), \(44 ÷ 2 = 22\), then \(18 - 55 + 22 = -15\).

Let's try interchanging '+' and '×': \(2 - 55 + 11 × 4 ÷ 18 = 2 - 55 + 44/18 ≈ 2-55+2.44 ≈ -50.56\)

Let's try interchanging '÷' and '+': \(2 - 55 + 11 × 4 ÷ 18 = 2 - 55 + 11 × 18 ÷ 4 = 2 - 55 + 49.5 = -2.5\)

It appears there's an error in the question or the provided options. None of the options lead to a result of zero.