In the following question, select the missing number from the given series.
241
The question asks us to find the missing number in the given series: 16, 17, 25, 52, 116, ?
To solve number series questions, we usually look for a pattern in the differences between consecutive terms, the ratios between terms, or a specific mathematical operation applied sequentially.
Let's examine the differences between consecutive terms in this series:
The sequence of differences is 1, 8, 27, 64. Let's analyze this new sequence to find a pattern.
We can observe that these differences are perfect cubes:
The pattern in the differences is the cube of consecutive natural numbers, starting from 1. The next difference in the series should be the cube of the next natural number, which is 5.
The next difference will be \(5^3\).
\(5^3 = 5 \times 5 \times 5 = 125\)
To find the missing number in the original series, we need to add this next difference (125) to the last term of the original series (116).
Missing number = Last term + Next difference
Missing number = \(116 + 125\)
Let's perform the addition:
| 116 |
| + 125 |
| ----- |
| 241 |
So, the missing number in the series is 241.
| Term | Value | Difference from Previous Term | Pattern in Difference |
|---|---|---|---|
| 1st | 16 | - | - |
| 2nd | 17 | \(17 - 16 = 1\) | \(1^3\) |
| 3rd | 25 | \(25 - 17 = 8\) | \(2^3\) |
| 4th | 52 | \(52 - 25 = 27\) | \(3^3\) |
| 5th | 116 | \(116 - 52 = 64\) | \(4^3\) |
| 6th (Missing) | ? | Next difference = \(5^3 = 125\) | \(5^3\) |
Adding the next difference (125) to the 5th term (116) gives \(116 + 125 = 241\).
Therefore, the missing number is 241.
Understanding common number series patterns is key to solving such questions.
| Pattern Type | Description | Example |
|---|---|---|
| Arithmetic Series | Constant difference between terms. | 2, 5, 8, 11, ... (difference = 3) |
| Geometric Series | Constant ratio between terms. | 3, 6, 12, 24, ... (ratio = 2) |
| Difference Series | The differences between terms follow a pattern (e.g., arithmetic, geometric, squares, cubes). This question is an example of a difference series based on cubes. | 1, 2, 4, 7, 11, ... (differences: 1, 2, 3, 4) |
| Square/Cube Series | Terms are squares or cubes, possibly with an addition or subtraction. | 1, 4, 9, 16, ... (\(1^2, 2^2, 3^2, 4^2\)) or 2, 5, 10, 17, ... (\(1^2+1, 2^2+1, 3^2+1, 4^2+1\)) |
| Fibonacci Series | Each term is the sum of the two preceding terms. | 0, 1, 1, 2, 3, 5, 8, ... |
| Alternating Series | Two different patterns alternate or terms alternate signs. | 1, 5, 2, 10, 3, 15, ... (Pattern 1: 1, 2, 3... Pattern 2: 5, 10, 15...) |
Here are some tips for approaching number series problems:
Select the number from among the given options that can replace the question mark (?) in the following series.
37, 52, 74, 104, 143, ?
Select the number that can replace the question mark (?) in the following series.
17, 19, 22, 27, 34, 45, 58,?Select the number from among the given options that can replace the question mark (?) in the following series.
10, 14, 31, 35, 73, 77, ?
Select the number from among the given options that can replace the question mark (?) in the following series.
215, 231, 256, 292, ?
Select the number from among the given options that can replace the question mark (?) in the following series.
6, 6, 8, 24, 28, 140, ?