Which two numbers (not individual digits) should be interchanged to make the given equation correct?
$56+ (11 \times 2) - (52 \div 4) + 16 = 76$
The question asks us to identify two numbers in the given equation that need to be swapped to make the equation mathematically correct. The equation provided is:
$$56 + (11 \times 2) - (52 \div 4) + 16 = 76$$
To find the solution, we will first check the value of the equation as it is and then test each option by interchanging the specified numbers.
We evaluate the left-hand side (LHS) of the equation using the order of operations (PEMDAS/BODMAS):
The LHS calculates to 81, which is not equal to the right-hand side (RHS) of 76. This confirms that an interchange is needed.
We will now check each option by swapping the mentioned numbers and recalculating the LHS.
| Option Numbers to Interchange | Resulting Equation | LHS Calculation Steps | LHS Result |
|---|---|---|---|
| 11 and 16 | $$56 + (16 \times 2) - (52 \div 4) + 11 = 76$$ | $56 + 32 - 13 + 11 = 88 - 13 + 11 = 75 + 11$ | 86 |
| 56 and 52 | $$52 + (11 \times 2) - (56 \div 4) + 16 = 76$$ | $52 + 22 - 14 + 16 = 74 - 14 + 16 = 60 + 16$ | 76 |
| 2 and 4 | $$56 + (11 \times 4) - (52 \div 2) + 16 = 76$$ | $56 + 44 - 26 + 16 = 100 - 26 + 16 = 74 + 16$ | 90 |
| 52 and 16 | $$56 + (11 \times 2) - (16 \div 4) + 52 = 76$$ | $56 + 22 - 4 + 52 = 78 - 4 + 52 = 74 + 52$ | 126 |
The table shows that swapping the numbers 56 and 52 results in the LHS equaling 76, which matches the RHS.
Let's confirm the calculation for this specific interchange:
The calculation confirms that $76 = 76$. Therefore, the correct numbers to interchange are 56 and 52.
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