Balancing the Equation $70*6*11*4$

The question asks us to find a sequence of mathematical operators to replace the '*' symbols in the expression $70*6*11*4$ to make the equation true. We need to test the given options.

Operator Sequence Analysis

Let's test the sequence provided in Option C: - x =. This means we replace the first '*' with '-', the second '*' with 'x' (multiplication), and the third '*' implies the result is the last number, 4.

The equation becomes:

$70 - 6 \times 11 = 4$

Applying Order of Operations

To solve this, we follow the standard order of operations (PEMDAS/BODMAS), which states that multiplication should be performed before subtraction.

• First, calculate the multiplication: $6 \times 11 = 66$
• Now substitute this back into the equation: $70 - 66 = 4$
• Perform the subtraction: $4 = 4$

Since $4 = 4$ is a true statement, the sequence of operators - x = correctly balances the equation.

Verifying Other Options (Briefly)

• Option 1 (+ x =): $70 + 6 \times 11 = 70 + 66 = 136 \neq 4$
• Option 2 (x + =): $70 \times 6 + 11 = 420 + 11 = 431 \neq 4$
• Option 4 (- ÷ =): $70 - 6 \div 11 = 70 - \frac{6}{11} \approx 70 - 0.545 \approx 69.45 \neq 4$

Therefore, the only sequence that balances the equation is - x =.