$12*108*6=8*4*2$
$+ \div \times -$
The problem requires finding the correct sequence of arithmetic signs to replace the asterisks (*) in the given equation: $12*108*6=8*4*2$. We need to test the options provided, substituting the signs and checking if the equation holds true, following the standard order of operations (PEMDAS/BODMAS).
Let's substitute the signs from Option D ($+$, $\div$, $\times$, $-$) into the equation:
$12 + 108 \div 6 = 8 \times 4 - 2$
Now, we evaluate both sides of the equation using the order of operations (division and multiplication before addition and subtraction):
Left Side:
Right Side:
Since the left side (30) equals the right side (30), the sequence of signs $+ \div \times -$ is correct.
The correct option uses the signs $+ \div \times -$ to satisfy the equation.
The value of $2^{2}+ \sqrt{ 10^{2} } -9 \sqrt{16} -17$ is
The value of 67 − 9 × [ 4 + 3 × { 16 − 8 ( 6 − 5 ) × 2} ÷ 32] is: