Which of the following sets of lengths (in cm) will give three sides of an obtuse-angled triangle?
15, 62, 64
To determine if a set of three lengths can form an obtuse-angled triangle, we need to check two conditions:
We will check each set of lengths provided in the options to see which one forms an obtuse-angled triangle.
Let the sides be $a=15$, $b=62$, and $c=64$. The longest side is $c=64$.
Let the sides be $a=17$, $b=64$, and $c=66$. The longest side is $c=66$.
Let the sides be $a=16$, $b=63$, and $c=65$. The longest side is $c=65$.
Let the sides be $a=18$, $b=65$, and $c=67$. The longest side is $c=67$.
Based on the analysis, only the set of lengths 15 cm, 62 cm, and 64 cm forms an obtuse-angled triangle.
| Side Lengths (cm) | Longest Side (c) | $a^2 + b^2$ | $c^2$ | Comparison ($a^2+b^2$ vs $c^2$) | Triangle Type |
|---|---|---|---|---|---|
| 15, 62, 64 | 64 | $15^2 + 62^2 = 225 + 3844 = 4069$ | $64^2 = 4096$ | $4069 < 4096$ | Obtuse-angled |
| 17, 64, 66 | 66 | $17^2 + 64^2 = 289 + 4096 = 4385$ | $66^2 = 4356$ | $4385 > 4356$ | Acute-angled |
| 16, 63, 65 | 65 | $16^2 + 63^2 = 256 + 3969 = 4225$ | $65^2 = 4225$ | $4225 = 4225$ | Right-angled |
| 18, 65, 67 | 67 | $18^2 + 65^2 = 324 + 4225 = 4549$ | $67^2 = 4489$ | $4549 > 4489$ | Acute-angled |
| Condition (c is longest side) | Triangle Type |
|---|---|
| $a + b \le c$ | Cannot form a triangle |
| $a^2 + b^2 < c^2$ | Obtuse-angled triangle |
| $a^2 + b^2 = c^2$ | Right-angled triangle |
| $a^2 + b^2 > c^2$ | Acute-angled triangle |
Triangles are fundamental shapes in geometry. They can be classified based on their side lengths (e.g., equilateral, isosceles, scalene) or based on their angles (acute, right, obtuse).
The relationship between the squares of the side lengths ($a^2 + b^2$ vs $c^2$) is a direct extension of the Pythagorean theorem, which specifically applies to right-angled triangles. This extended relationship allows us to determine the type of triangle even when it's not a right triangle, simply by knowing its side lengths.
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