A 15 cm long perpendicular is drawn from the centre of a circle to a 40 cm long chord. Find the diameter of the circle.
50 cm
The problem asks us to find the diameter of a circle given the length of a chord and the perpendicular distance from the center of the circle to that chord. This is a classic geometry problem involving the properties of circles.
We are given:
We need to find the diameter of the circle.
A fundamental theorem in circle geometry states that a perpendicular drawn from the center of a circle to a chord bisects the chord. This means it divides the chord into two equal parts.
Given the chord length is 40 cm, the perpendicular from the center bisects it into two segments of equal length.
Half-chord length $$ = \frac{\text{Chord Length}}{2} $$
Half-chord length $$ = \frac{40 \text{ cm}}{2} $$
Half-chord length $$ = 20 \text{ cm} $$
Consider the radius of the circle drawn to one end of the chord. This radius, the perpendicular from the center to the chord, and the half-chord form a right-angled triangle. The right angle is at the point where the perpendicular meets the chord.
In a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. The Pythagorean theorem is stated as $$a^2 + b^2 = c^2$$, where $$a$$ and $$b$$ are the lengths of the legs, and $$c$$ is the length of the hypotenuse.
In our case:
Using the Pythagorean theorem:
$$ r^2 = 15^2 + 20^2 $$
$$ r^2 = 225 + 400 $$
$$ r^2 = 625 $$
To find the radius $$r$$, we take the square root of 625:
$$ r = \sqrt{625} $$
$$ r = 25 \text{ cm} $$
The diameter of a circle is twice its radius.
Diameter $$ = 2 \times \text{Radius} $$
Diameter $$ = 2 \times 25 \text{ cm} $$
Diameter $$ = 50 \text{ cm} $$
The diameter of the circle is 50 cm.
| Given Information | Calculated Values |
|---|---|
| Perpendicular distance from center = 15 cm | Half-chord length = 20 cm |
| Chord length = 40 cm | Radius = 25 cm |
| Diameter = 50 cm |
| Term | Definition |
|---|---|
| Circle | A set of all points in a plane that are at a fixed distance from a fixed point (the center). |
| Center | The fixed point inside the circle from which all points on the circle are equidistant. |
| Radius ($$r$$) | The distance from the center to any point on the circle. |
| Diameter ($$d$$) | A line segment passing through the center with endpoints on the circle. It is twice the radius ($$d=2r$$). |
| Chord | A line segment connecting any two points on the circle. |
| Perpendicular Bisector of a Chord | A line perpendicular to a chord that passes through its midpoint. This line always passes through the center of the circle. |
| Pythagorean Theorem | In a right-angled triangle with legs $$a$$, $$b$$ and hypotenuse $$c$$, $$a^2 + b^2 = c^2$$. |
Problems involving chords, radii, and the center of a circle often require understanding the relationships between these elements. The property that a perpendicular from the center bisects the chord is very useful.
Mastering these concepts helps in solving various circle geometry problems.
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