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Question

A 15 cm long perpendicular is drawn from the centre of a circle to a 40 cm long chord. Find the diameter of the circle.

This question was previously asked in
SSC CGL 2023 (Tier-II) Paper 1 Previous Year Paper (26-Oct-2023) (Shift-1)
The correct answer is

50 cm

Finding the Diameter of a Circle Using Chord Length and Perpendicular Distance

The problem asks us to find the diameter of a circle given the length of a chord and the perpendicular distance from the center of the circle to that chord. This is a classic geometry problem involving the properties of circles.

Understanding the Problem Setup

We are given:

  • Length of the perpendicular from the center to the chord = 15 cm
  • Length of the chord = 40 cm

We need to find the diameter of the circle.

Key Geometric Principle: Perpendicular from Center to Chord

A fundamental theorem in circle geometry states that a perpendicular drawn from the center of a circle to a chord bisects the chord. This means it divides the chord into two equal parts.

Calculating the Half-Chord Length

Given the chord length is 40 cm, the perpendicular from the center bisects it into two segments of equal length.

Half-chord length $$ = \frac{\text{Chord Length}}{2} $$

Half-chord length $$ = \frac{40 \text{ cm}}{2} $$

Half-chord length $$ = 20 \text{ cm} $$

Forming a Right-Angled Triangle

Consider the radius of the circle drawn to one end of the chord. This radius, the perpendicular from the center to the chord, and the half-chord form a right-angled triangle. The right angle is at the point where the perpendicular meets the chord.

  • One leg of the right triangle is the perpendicular distance from the center to the chord (15 cm).
  • The other leg is the half-chord length (20 cm).
  • The hypotenuse of the right triangle is the radius of the circle (let's call it $$r$$).

Applying the Pythagorean Theorem

In a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. The Pythagorean theorem is stated as $$a^2 + b^2 = c^2$$, where $$a$$ and $$b$$ are the lengths of the legs, and $$c$$ is the length of the hypotenuse.

In our case:

  • Leg 1 $$= 15 \text{ cm}$$ (perpendicular distance)
  • Leg 2 $$= 20 \text{ cm}$$ (half-chord length)
  • Hypotenuse $$= r$$ (radius)

Using the Pythagorean theorem:

$$ r^2 = 15^2 + 20^2 $$

$$ r^2 = 225 + 400 $$

$$ r^2 = 625 $$

To find the radius $$r$$, we take the square root of 625:

$$ r = \sqrt{625} $$

$$ r = 25 \text{ cm} $$

Calculating the Diameter

The diameter of a circle is twice its radius.

Diameter $$ = 2 \times \text{Radius} $$

Diameter $$ = 2 \times 25 \text{ cm} $$

Diameter $$ = 50 \text{ cm} $$

Final Answer

The diameter of the circle is 50 cm.

Given Information Calculated Values
Perpendicular distance from center = 15 cm Half-chord length = 20 cm
Chord length = 40 cm Radius = 25 cm
Diameter = 50 cm

Revision Table: Circle Geometry Concepts

Term Definition
Circle A set of all points in a plane that are at a fixed distance from a fixed point (the center).
Center The fixed point inside the circle from which all points on the circle are equidistant.
Radius ($$r$$) The distance from the center to any point on the circle.
Diameter ($$d$$) A line segment passing through the center with endpoints on the circle. It is twice the radius ($$d=2r$$).
Chord A line segment connecting any two points on the circle.
Perpendicular Bisector of a Chord A line perpendicular to a chord that passes through its midpoint. This line always passes through the center of the circle.
Pythagorean Theorem In a right-angled triangle with legs $$a$$, $$b$$ and hypotenuse $$c$$, $$a^2 + b^2 = c^2$$.

Additional Information on Circle Properties and Calculations

Problems involving chords, radii, and the center of a circle often require understanding the relationships between these elements. The property that a perpendicular from the center bisects the chord is very useful.

  • If you know the radius and the distance of a chord from the center, you can find the chord length using the Pythagorean theorem.
  • If you know the radius and the chord length, you can find the distance of the chord from the center using the Pythagorean theorem.
  • The longest chord in a circle is the diameter.

Mastering these concepts helps in solving various circle geometry problems.

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Similar Questions

  1. A 15 cm long perpendicular is drawn from the centre of a circle to its 40 cm long chord. Find the radius of the circle.

  2. The area of two triangles is in the ratio 5 ∶ 3 and their heights are in the ratio 5 ∶ 7. Find the ratio of their bases. 

  3. The perimeter of an equilateral triangle is 48 cm. Find its area (in cm2).

  4. Find the length of the arc of the sector of a circle of diameter 7 cm with a central angle of 108°. [Use π = 22/7]  

  5. Which of the following sets of lengths (in cm) will give three sides of an obtuse-angled triangle?

  6. A circular arc whose radius is 4 cm makes an angle 45° at the centre. Find the perimeter of the sector formed.

    (Take π = \(\frac{22}{7}\))

  7. Select the correct statement about the properties of a triangle.

  8. The side of an equilateral triangle is 12 cm. What is the radius of the circle circumscribing this equilateral triangle?

  9. The ratio of the outer and the inner circumference of a circular path is 5 ∶ 4. If path is 50 metres wide, then what is the radius of the inner circle?

  10. The diagonal of the square is 8√2 cm. Find the diagonal of another square whose area is triple that of the first square.


Important Questions from Plane Figures

  1. A wheel makes 4000 revolution is covering a distance of 60 km. The radius of the wheel is:

  2. A person bought a rectangular piece of land whose length and breadth are in the ratio 7 : 5. If the cost of fencing the land is ₹2,880 at the rate of ₹15/m, then what is the length of the land?

  3. If the diameter of a circle increases by 15%, then what will be the percentage increase in its area?

  4. The areas of two squares are 16 : 9. The ratio of their perimeter is:

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