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Question

The side of an equilateral triangle is 12 cm. What is the radius of the circle circumscribing this equilateral triangle?

This question was previously asked in
SSC CGL 2022 Tier-II (Paper 2 JSO) Previous Year Paper (04-Mar-2023)
The correct answer is 4√3 cm

Calculating the Circumradius of an Equilateral Triangle

The question asks us to find the radius of the circle that circumscribes an equilateral triangle with a side length of 12 cm.

A circle that circumscribes a triangle passes through all three vertices of the triangle. The radius of this circle is called the circumradius.

Formula for Circumradius of an Equilateral Triangle

For an equilateral triangle with a side length 'a', the radius (R) of the circumscribing circle is given by the formula:

\( R = \frac{a}{\sqrt{3}} \)

Alternatively, the circumradius can also be calculated using the height 'h' of the equilateral triangle. The height of an equilateral triangle with side 'a' is \( h = \frac{a\sqrt{3}}{2} \). The circumcenter (center of the circumscribing circle) is also the centroid, which divides the median (and height) in the ratio 2:1. So, the circumradius R is \( \frac{2}{3} \) of the height h:

\( R = \frac{2}{3} h = \frac{2}{3} \times \frac{a\sqrt{3}}{2} = \frac{a\sqrt{3}}{3} \)

Let's use the first formula \( R = \frac{a}{\sqrt{3}} \) as it directly uses the side length.

Step-by-Step Calculation

Given the side length of the equilateral triangle, \( a = 12 \) cm.

Using the formula \( R = \frac{a}{\sqrt{3}} \):

\( R = \frac{12}{\sqrt{3}} \)

To rationalize the denominator, we multiply the numerator and the denominator by \( \sqrt{3} \):

\( R = \frac{12}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}} \)

\( R = \frac{12\sqrt{3}}{3} \)

Now, simplify the expression:

\( R = 4\sqrt{3} \)

So, the radius of the circle circumscribing the equilateral triangle is \( 4\sqrt{3} \) cm.

Result Summary

Given side length \( a = 12 \) cm.

Circumradius \( R = 4\sqrt{3} \) cm.

Given Formula Used Calculation Result
Side length \( a = 12 \) cm \( R = \frac{a}{\sqrt{3}} \) \( R = \frac{12}{\sqrt{3}} = \frac{12\sqrt{3}}{3} = 4\sqrt{3} \) \( R = 4\sqrt{3} \) cm

Revision Table: Equilateral Triangle Properties

Property Formula (side 'a') Formula (height 'h') Notes
Height (h) \( h = \frac{a\sqrt{3}}{2} \) - Also a median, angle bisector, perpendicular bisector
Area (A) \( A = \frac{\sqrt{3}}{4} a^2 \) \( A = \frac{1}{2} a h \) -
Circumradius (R) \( R = \frac{a}{\sqrt{3}} = \frac{a\sqrt{3}}{3} \) \( R = \frac{2}{3} h \) Radius of circumscribing circle
Inradius (r) \( r = \frac{a}{2\sqrt{3}} = \frac{a\sqrt{3}}{6} \) \( r = \frac{1}{3} h \) Radius of inscribing circle
Relation R and r \( R = 2r \) \( R = 2r \) Circumradius is twice the inradius

Additional Information: Equilateral Triangle Centers

In an equilateral triangle, several important centers coincide at a single point:

  • Circumcenter: The center of the circumscribing circle. It is the intersection of the perpendicular bisectors of the sides.
  • Incenter: The center of the inscribed circle. It is the intersection of the angle bisectors.
  • Centroid: The intersection of the medians. It divides each median in a 2:1 ratio.
  • Orthocenter: The intersection of the altitudes.

This unique property simplifies calculations related to circles and points of concurrency in equilateral triangles. The circumradius is the distance from this central point to any vertex, and the inradius is the distance from this point to any side (measured perpendicularly).

In this problem, we found the circumradius using the side length, confirming one of the standard formulas for equilateral triangles.

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