Which of the following is the work done by the gravitational force on the object of mass 50 kg when the object is moved from one point to another point along a horizontal line (g = 10 m/s²)?
Zero
The work done by a force is defined as the dot product of the force and the displacement vector: \(W = \vec{F} \cdot \vec{d} = Fd\cos\theta\), where \(F\) is the magnitude of the force, \(d\) is the magnitude of the displacement, and \(\theta\) is the angle between the force and displacement vectors.
In this case, the gravitational force acts vertically downwards (towards the center of the Earth), while the object is moved along a horizontal line. Therefore, the angle between the gravitational force and the displacement vector is 90 degrees (\(\theta = 90^\circ\)).
Since \(\cos(90^\circ) = 0\), the work done by the gravitational force is:
\(W = Fd\cos(90^\circ) = Fd(0) = 0\)
The mass of the object (50 kg) and the acceleration due to gravity (g = 10 m/s²) are irrelevant because the gravitational force is perpendicular to the displacement. Regardless of the distance moved horizontally, no work is done by gravity.
Therefore, the correct answer is Zero.
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