To find the kinetic energy (KE) of an object, we use the following information:
The formula to calculate kinetic energy is:
\( KE = \frac{1}{2}mv^2 \)
Substitute the given values into the kinetic energy formula:
\( KE = \frac{1}{2} \times (1 \, \text{kg}) \times (10 \, \text{m/s})^2 \)
\( (10 \, \text{m/s})^2 = 100 \, \text{m}^2/\text{s}^2 \)
\( KE = \frac{1}{2} \times 1 \, \text{kg} \times 100 \, \text{m}^2/\text{s}^2 \)
\( KE = 0.5 \times 100 \, \text{kg} \cdot \text{m}^2/\text{s}^2 \)
\( KE = 50 \, \text{J} \)
(Note: 1 kg⋅m²/s² is equal to 1 Joule, J)
The kinetic energy of the object is 50 J.
Which of the following is an example of potential energy?
_______ is one of the chemical used to produce Ocean Thermal Energy.
A body of mass 2kg is thrown up vertically with a kinetic energy of 500J. If the acceleration due to gravity is 10 m/s2, the height at which the kinetic energy of the body becomes half of the original values is _____
Arjun has a mass of 50 kg, he eats banana of 1000 calories. If this energy is used up to lift him from the ground, the height to which he can climb is _______. Take g = 10 m/s2 and 1 calories = 4.2 Joule.
When a body of mass 'm' attains a velocity 'v' from rest in time 't', then kinetic energy of translation is: