This problem involves the concepts of kinetic energy, work done, and force. The key principle connecting these is the Work-Energy Theorem.
We are given that both the lorry and the car have the same initial kinetic energy ($KE$) and are stopped by the same retarding force ($F$).
Using the Work-Energy Theorem, the work done by the retarding force equals the change in kinetic energy.
From these equations, we can solve for the stopping distance ($d$):
Since both $KE$ (initial kinetic energy) and $F$ (retarding force) are the same for the lorry and the car, their stopping distances ($d$) must also be the same.
Both the lorry and the car will come to rest in the same distance because they possess the same initial kinetic energy and are acted upon by the same magnitude of retarding force.
Which of the following is an example of potential energy?
_______ is one of the chemical used to produce Ocean Thermal Energy.
A body of mass 2kg is thrown up vertically with a kinetic energy of 500J. If the acceleration due to gravity is 10 m/s2, the height at which the kinetic energy of the body becomes half of the original values is _____
Arjun has a mass of 50 kg, he eats banana of 1000 calories. If this energy is used up to lift him from the ground, the height to which he can climb is _______. Take g = 10 m/s2 and 1 calories = 4.2 Joule.
When a body of mass 'm' attains a velocity 'v' from rest in time 't', then kinetic energy of translation is: