Question
Which of the following is the largest 5-digit number divisible by 47?
This question was previously asked in
SSC CGL 2024 (Tier-I) Previous Year Paper (17-Sep-2024) (Shift 3)
The correct answer is
99,969
The largest 5-digit number is 99,999. Dividing it by 47 gives a remainder of 30. Subtracting the remainder from 99,999 gives 99,969, which is divisible by 47.
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Important Questions from Number System
A frog was at the bottom of an 80 m deep well. It attempted to come out of it by jumping. In each jump, it covered 1.15 m but slipped down by 0.75 m. The number of jumps after which it would be out of the well is:
The smallest perfect square number divisible by each of 6 and 12 is:
The L.C.M. of two different numbers are 30. Which of the following cannot be their H.C.F.?
Which is the least four-digit number which when divided by 5, 6 and 8 leaves remainder 2 in each case?
- A number when divided by 5 leaves a remainder 3.
What is the remainder when its square is divided by 5?
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