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Question

Which number among 38211, 38121, 32118, and 31128 is divisible by 24?

This question was previously asked in
SSC CGL 2024 (Tier-I) Previous Year Paper (17-Sep-2024) (Shift 3)
The correct answer is

31128

A number is divisible by 24 if it is divisible by both 3 and 8. 

Let's check each number: 32118: 

Divisible by 2 (even) but not by 3 (sum of digits is 15, divisible by 3). 

Divisible by 8 (last three digits 118 are not divisible by 8). 

38121: Not divisible by 2 or 8. 

38211: Not divisible by 2 or 8. 

31128: Divisible by 2 (even). 

Divisible by 8 (last three digits 128 are divisible by 8). 

Sum of digits is 15 (divisible by 3). 

Therefore, 31128 is divisible by 24 (3 x 8 = 24).

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