Which number among 38211, 38121, 32118, and 31128 is divisible by 24?
31128
A number is divisible by 24 if it is divisible by both 3 and 8.
Let's check each number: 32118:
Divisible by 2 (even) but not by 3 (sum of digits is 15, divisible by 3).
Divisible by 8 (last three digits 118 are not divisible by 8).
38121: Not divisible by 2 or 8.
38211: Not divisible by 2 or 8.
31128: Divisible by 2 (even).
Divisible by 8 (last three digits 128 are divisible by 8).
Sum of digits is 15 (divisible by 3).
Therefore, 31128 is divisible by 24 (3 x 8 = 24).
Important Questions from Number System
A frog was at the bottom of an 80 m deep well. It attempted to come out of it by jumping. In each jump, it covered 1.15 m but slipped down by 0.75 m. The number of jumps after which it would be out of the well is:
The smallest perfect square number divisible by each of 6 and 12 is:
The L.C.M. of two different numbers are 30. Which of the following cannot be their H.C.F.?
Which is the least four-digit number which when divided by 5, 6 and 8 leaves remainder 2 in each case?
- A number when divided by 5 leaves a remainder 3.
What is the remainder when its square is divided by 5?
