Which of the following digital modulation systems support high bit rate ?
PSK
Phase-shift keying is the scheme that scales to high bit rates — option 2 — and it does so for two independent reasons.
First, it is the most bandwidth-efficient of the three. FSK must reserve room for two separate carrier frequencies plus their sidebands, so by Carson's rule its bandwidth is
\(BW_{FSK}=2\left(\Delta f+R_{b}\right)\)
against \(2R_{b}\) for ASK and PSK. For a given channel width, PSK therefore carries more bits per second.
Second, and more importantly, it extends to M-ary signalling. Phase can be divided finely and evenly round a circle — 4-PSK, 8-PSK, 16-QAM and beyond — and each doubling of the constellation adds one bit per symbol:
\(R_{b}=R_{s}\log_{2}M\)
so QPSK sends two bits per symbol in the same bandwidth as BPSK. Amplitude cannot be subdivided so freely, because the levels crowd together in noise and the peak power must rise; frequency cannot, because each extra tone costs more spectrum. All high-rate systems — modems, Wi-Fi, LTE, satellite links — are built on phase and quadrature-amplitude constellations for exactly this reason.
| ASK | FSK | PSK | |
|---|---|---|---|
| Bandwidth | 2Rb | Widest | 2Rb |
| Noise immunity | Poor | Good | Best |
| Constant envelope | No | Yes | Yes |
| M-ary extension | Limited | Costly in spectrum | Natural |
The error performance points the same way. For coherent detection, BPSK needs 3 dB less energy per bit than FSK for the same error rate:
\(P_{e,PSK}=Q\left(\sqrt{\dfrac{2E_{b}}{N_{0}}}\right),\qquad P_{e,FSK}=Q\left(\sqrt{\dfrac{E_{b}}{N_{0}}}\right)\)
because antipodal symbols are as far apart as a given energy allows. ASK is worse still, since noise adds directly to the amplitude that carries the information.
Flagged because "high bit rate" is not a quantitative criterion; but on bandwidth efficiency, noise performance and extensibility alike, PSK is the answer.
Binary ASK modulation gives
ST1 : High noise immunity
ST2 : Large bandwidth
In coherent binary FSK system the orthogonal sinusoidal signals of frequency 20 kHz and 50 kHz are used to represent '0' and '1' respectively. The maximum possible bit interval is:
Which of the following statements are correct :
(a) ASK gives a maximum probability of error.
(b) FSK is also known as ON-OFF keying.
(c) In DPSK, no synchronous carrier is needed at the receiver.
(d) Probability of Error in DPSK is less than BPSK.
In digital data transmission, a line code should have the following properties
(A) Transmission bandwidth should be as small as possible
(B) Transmitted power should be as high as possible
(C) Transmission bandwidth should be as high as possible
(D) Transmitted power should be as low as possible
Choose the correct answer from the options given below:
If the in‐phase and quadrature components in an M‐ary PSK system are permitted to be independent, then this scheme becomes a:
Which of the following statements are correct?
A. M‐ary modulation scheme is preferable where the bandwidth requirement is important.
B. M‐ary PSK system considers 'M' different phases in the range 'π/2'.
C. In M‐ary modulation scheme, only coherent detection is possible.
D. M‐ary QAM scheme uses 'm 2' carrier signals having the same frequency.
Choose the correct answer from the options given below:
In digital communication, Inter Symbol Interference (ISI) is a form of distortion where one symbol interferes with subsequent symbols. An eye diagram is used to study the extent of ISI in a communication channel. Which of the following is FALSE?
The data rate of QPSK is ______ as that of BPSK for the same symbol rate.