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Question

When a number x is divided by a divisor it is seen that the divisor = 4 times the quotient = double the remainder. If the remainder is 80 then the value of x is

This question was previously asked in
SSC CGL 2016 (Tier 1) Previous Year Question Paper (11-Sep-2016) (Shift 2)
The correct answer is

6480

Understanding the Division Problem and Finding the Number

The problem asks us to find the value of a number, let's call it x, based on the relationships between the divisor, quotient, and remainder when x is divided by a divisor. We are given specific conditions that link these three components of the division process.

Given Information and Relationships

We are provided with the following information:

  • A number x is divided by a divisor.
  • The divisor is equal to 4 times the quotient. Mathematically, this can be written as: $$ \text{Divisor} = 4 \times \text{Quotient} $$
  • The divisor is also equal to double the remainder. Mathematically, this can be written as: $$ \text{Divisor} = 2 \times \text{Remainder} $$
  • The remainder is given as 80. Mathematically, this is: $$ \text{Remainder} = 80 $$

Step-by-Step Calculation to Find the Number x

Step 1: Find the Divisor

We know that the divisor is double the remainder, and the remainder is 80. Using the relationship Divisor = 2 × Remainder, we can find the divisor:

$$ \text{Divisor} = 2 \times 80 $$ $$ \text{Divisor} = 160 $$

So, the divisor is 160.

Step 2: Find the Quotient

We also know that the divisor is 4 times the quotient. We have just calculated the divisor as 160. Using the relationship Divisor = 4 × Quotient, we can find the quotient:

$$ 160 = 4 \times \text{Quotient} $$

To find the Quotient, we divide 160 by 4:

$$ \text{Quotient} = \frac{160}{4} $$ $$ \text{Quotient} = 40 $$

So, the quotient is 40.

Step 3: Find the Number x using the Division Algorithm

The fundamental relationship in division, known as the Division Algorithm or Division Lemma, states that for any integer x (dividend) and a positive integer divisor, there exist unique integers quotient and remainder such that:

$$ x = \text{Divisor} \times \text{Quotient} + \text{Remainder} $$

We have found the following values:

  • Divisor = 160
  • Quotient = 40
  • Remainder = 80

Now, we can substitute these values into the Division Algorithm formula to find the number x:

$$ x = 160 \times 40 + 80 $$

First, calculate the product of the divisor and the quotient:

$$ 160 \times 40 = 6400 $$

Next, add the remainder to this product:

$$ x = 6400 + 80 $$ $$ x = 6480 $$

Conclusion

Based on the given conditions and calculations, the value of the number x is 6480.

Summary of Division Components
Component Value
Remainder 80
Divisor 160
Quotient 40
Number (x) 6480

Revision Table: Key Concepts in Division

Division Concepts Review
Term Definition Relationship
Dividend (x) The number being divided. \(x = \text{Divisor} \times \text{Quotient} + \text{Remainder}\)
Divisor The number by which the dividend is divided. Given relationships (e.g., \(4 \times \text{Quotient}\), \(2 \times \text{Remainder}\))
Quotient The result of the division (how many times the divisor fits into the dividend). Found using given relationships involving Divisor.
Remainder The amount left over after division. Must be less than the Divisor (\(0 \le \text{Remainder} < \text{Divisor}\))

Additional Information: Division Algorithm Explained

The Division Algorithm is a foundational theorem in number theory. It precisely defines the relationship between a dividend, a divisor, a quotient, and a remainder. For any integer dividend 'a' and any positive integer divisor 'b', there are unique integers 'q' (quotient) and 'r' (remainder) such that:

$$ a = bq + r $$

where the remainder 'r' satisfies the condition 0 ≤ r < b. This means the remainder is always non-negative and strictly less than the absolute value of the divisor. In our specific problem, the divisor is positive, so 0 ≤ Remainder < Divisor.

In this question:

  • Dividend (a) is the number x we are looking for.
  • Divisor (b) is 160.
  • Quotient (q) is 40.
  • Remainder (r) is 80.

And we verified that $80 < 160$, satisfying the condition for the remainder.

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