To find the point that divides a line segment internally in a given ratio, we use the section formula.
Let the two points be \(P(x_1, y_1) = (10, 18)\) and \(Q(x_2, y_2) = (5, 8)\). Let the ratio be \(m : n = 2 : 3\).
The coordinates \((x, y)\) of the point dividing the line segment internally are given by the section formula:
\(x = \frac{mx_2 + nx_1}{m+n}\) \(y = \frac{my_2 + ny_1}{m+n}\)Substitute the given values into the formula:
X-coordinate calculation:
\(x = \frac{(2 \times 5) + (3 \times 10)}{2+3}\) \(x = \frac{10 + 30}{5}\) \(x = \frac{40}{5}\) \(x = 8\)Y-coordinate calculation:
\(y = \frac{(2 \times 8) + (3 \times 18)}{2+3}\) \(y = \frac{16 + 54}{5}\) \(y = \frac{70}{5}\) \(y = 14\)Therefore, the point dividing the line segment internally is \((8, 14)\).
The calculated point \((8, 14)\) matches Option 3.
Find the co-ordinates of the centroid of a triangle whose vertices are A(1, 4), B(7, 8) and C(10, 12).