Find the co-ordinates of the centroid of a triangle whose vertices are A(1, 4), B(7, 8) and C(10, 12).
The problem asks us to find the coordinates of the centroid of a triangle given its vertices A, B, and C.
The centroid is the point where the three medians of a triangle intersect. A median connects a vertex to the midpoint of the opposite side. The centroid is also known as the center of gravity or the geometric center of the triangle.
For a triangle with vertices $(x_1, y_1)$, $(x_2, y_2)$, and $(x_3, y_3)$, the coordinates of the centroid (G) are calculated using the following formula:
$$ G = \left( \frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3} \right) $$We sum the x-coordinates of the vertices and divide by 3:
$$ \text{Centroid x} = \frac{x_1 + x_2 + x_3}{3} $$ $$ \text{Centroid x} = \frac{1 + 7 + 10}{3} $$ $$ \text{Centroid x} = \frac{18}{3} $$ $$ \text{Centroid x} = 6 $$We sum the y-coordinates of the vertices and divide by 3:
$$ \text{Centroid y} = \frac{y_1 + y_2 + y_3}{3} $$ $$ \text{Centroid y} = \frac{4 + 8 + 12}{3} $$ $$ \text{Centroid y} = \frac{24}{3} $$ $$ \text{Centroid y} = 8 $$The calculated coordinates of the centroid are $(6, 8)$.
Comparing our result with the given options:
The calculated coordinates $(6, 8)$ match Option 2.