The problem asks for the initial sum of money (Principal, P) that will grow to a total amount (A) of ₹2,400 after 4 years (T) at a simple interest rate (R) of 5% per annum.
The formula for the Amount (A) in simple interest is:
A = P + SI
Where SI (Simple Interest) is calculated as:
SI = $ \frac{P \times R \times T}{100} $
Substituting the SI formula into the Amount formula:
A = P + $ \frac{P \times R \times T}{100} $
Factor out P:
A = P $ \left(1 + \frac{R \times T}{100}\right) $
We are given:
Substitute these values into the formula:
₹2,400 = P $ \left(1 + \frac{5 \times 4}{100}\right) $
₹2,400 = P $ \left(1 + \frac{20}{100}\right) $
₹2,400 = P $ \left(1 + 0.20\right) $
₹2,400 = P $ (1.20) $
To find the principal sum (P), rearrange the equation:
P = $ \frac{₹2,400}{1.20} $
P = $ \frac{24000}{12} $
P = ₹2,000
The sum of money that will amount to ₹2,400 at 5% simple interest in 4 years is ₹2,000.
Anil lent a sum of Rs. 5,000 on simple interest for 10 years in such a way that the rate of interest is 6% per annum for the first 2 years, 8% per anmum for the next 2 years and 10% per annum beyond 4 years. How much interest (in Rs.) will he earn at the end of 10 years?
What will be the simple interest on a sum of Rs. 12000 at the rate of 15 percent per annum for three years ?
If in 13 years fixed sum doubles at simple interest, what will be the interest rate per year? (correct to two decimal places)
On simple interest a sum of Rs. 640 becomes Rs. 832 in 2 years. What will Rs. 860 become in 4 years at the same rate of simple interest?
A certain sum amounts to Rs. 81840 in 3 years and to Rs. 92400 in 5 years at x% p.a. under simple interest. If the rate of interest is becomes (x + 2)%, then in how many years will the same sum double itself?