On simple interest a sum of Rs. 640 becomes Rs. 832 in 2 years. What will Rs. 860 become in 4 years at the same rate of simple interest?
Rs. 1,376
This problem involves calculating the final amount on a sum of money based on simple interest. First, we need to determine the rate of simple interest from the initial information provided. Then, using this rate, we calculate the simple interest and the final amount for the second sum over a different period.
The first part of the question gives us the initial principal amount, the final amount after a certain time, and the time period. We can use this to find the simple interest earned and then the rate of interest per annum.
The simple interest ($\text{SI}_1$) earned is the difference between the amount and the principal:
\text{SI}_1 = \text{A}_1 - \text{P}_1
\text{SI}_1 = 832 - 640
\text{SI}_1 = 192 \text{ Rs.}
The formula for simple interest is:
\text{SI} = \frac{\text{P} \times \text{R} \times \text{T}}{100}
Where P is Principal, R is the Rate of Interest per annum, and T is the Time in years.
We can rearrange this formula to find the rate (R):
\text{R} = \frac{\text{SI} \times 100}{\text{P} \times \text{T}}
Substituting the values from the first scenario:
\text{R} = \frac{192 \times 100}{640 \times 2}
\text{R} = \frac{19200}{1280}
\text{R} = \frac{1920}{128}
Let's simplify this fraction:
\text{R} = \frac{1920 \div 64}{128 \div 64} = \frac{30}{2} = 15
So, the simple interest rate is 15% per annum.
Now we use the rate (R = 15%) calculated in Step 1 to find the amount for the second principal over the given time period.
First, calculate the simple interest ($\text{SI}_2$) for the second sum:
\text{SI}_2 = \frac{\text{P}_2 \times \text{R} \times \text{T}_2}{100}
\text{SI}_2 = \frac{860 \times 15 \times 4}{100}
\text{SI}_2 = \frac{860 \times 60}{100}
\text{SI}_2 = \frac{86 \times 60}{10}
\text{SI}_2 = 86 \times 6
\text{SI}_2 = 516 \text{ Rs.}
The final amount ($\text{A}_2$) will be the sum of the new principal and the simple interest earned:
\text{A}_2 = \text{P}_2 + \text{SI}_2
\text{A}_2 = 860 + 516
\text{A}_2 = 1376 \text{ Rs.}
| Scenario | Principal (P) | Time (T) | Amount (A) | Simple Interest (SI = A - P) | Rate ($\text{R} = \frac{\text{SI} \times 100}{\text{P} \times \text{T}}$) |
|---|---|---|---|---|---|
| 1 | Rs. 640 | 2 years | Rs. 832 | Rs. 192 | 15% |
| 2 | Rs. 860 | 4 years | Rs. 1376 (Calculated) | Rs. 516 (Calculated) | 15% |
Therefore, Rs. 860 will become Rs. 1,376 in 4 years at the same rate of simple interest.
| Concept | Description | Formula (Simple Interest) |
|---|---|---|
| Principal | The initial amount of money borrowed or invested. | P |
| Amount | The total sum at the end of the period, including principal and interest. | A = P + SI |
| Simple Interest (SI) | Interest calculated only on the principal amount. | $\text{SI} = \frac{\text{P} \times \text{R} \times \text{T}}{100}$ |
| Rate (R) | The percentage of the principal charged as interest per year. | $\text{R} = \frac{\text{SI} \times 100}{\text{P} \times \text{T}}$ |
| Time (T) | The duration for which the money is borrowed or invested, usually in years. | T |
It's important to understand the difference between simple interest and compound interest.
This question specifically deals with simple interest, where the calculation is straightforward based on the original principal amount only.
Anil lent a sum of Rs. 5,000 on simple interest for 10 years in such a way that the rate of interest is 6% per annum for the first 2 years, 8% per anmum for the next 2 years and 10% per annum beyond 4 years. How much interest (in Rs.) will he earn at the end of 10 years?
What will be the simple interest on a sum of Rs. 12000 at the rate of 15 percent per annum for three years ?
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A sum of money at simple interest amounts to Rs. 6,000 in 4 years and to Rs. 6,750 in 7 years at the same rate per cent p.a. of interest. The sum (in Rs.) is: