Anil lent a sum of Rs. 5,000 on simple interest for 10 years in such a way that the rate of interest is 6% per annum for the first 2 years, 8% per anmum for the next 2 years and 10% per annum beyond 4 years. How much interest (in Rs.) will he earn at the end of 10 years?
4,400
This problem involves calculating the total simple interest earned on a principal amount when the interest rate changes over the investment period. We need to break down the total time into segments based on the different interest rates and calculate the simple interest for each segment. The total interest will be the sum of the simple interests from all segments.
The principal amount is Rs. 5,000, and the total duration is 10 years.
The interest rates are applied as follows:
Let's determine the duration for each rate period:
The formula for simple interest (SI) is:
\( \text{SI} = \frac{\text{Principal} \times \text{Rate} \times \text{Time}}{100} \)
Let's calculate the simple interest for each period using the principal amount of Rs. 5,000.
Principal (P) = Rs. 5,000
Rate (R1) = 6% per annum
Time (T1) = 2 years
Simple Interest 1 (SI1) = \( \frac{5000 \times 6 \times 2}{100} \)
SI1 = \( \frac{60000}{100} \)
SI1 = Rs. 600
Principal (P) = Rs. 5,000
Rate (R2) = 8% per annum
Time (T2) = 2 years
Simple Interest 2 (SI2) = \( \frac{5000 \times 8 \times 2}{100} \)
SI2 = \( \frac{80000}{100} \)
SI2 = Rs. 800
Principal (P) = Rs. 5,000
Rate (R3) = 10% per annum
Time (T3) = 6 years
Simple Interest 3 (SI3) = \( \frac{5000 \times 10 \times 6}{100} \)
SI3 = \( \frac{300000}{100} \)
SI3 = Rs. 3,000
The total simple interest earned over 10 years is the sum of the interests from all three periods:
Total SI = SI1 + SI2 + SI3
Total SI = 600 + 800 + 3000
Total SI = Rs. 4,400
Thus, Anil will earn a total simple interest of Rs. 4,400 at the end of 10 years.
| Period | Years | Rate (%) | Principal (Rs.) | Simple Interest Calculation | Simple Interest (Rs.) |
|---|---|---|---|---|---|
| 1 | 2 | 6 | 5000 | \( \frac{5000 \times 6 \times 2}{100} \) | 600 |
| 2 | 2 | 8 | 5000 | \( \frac{5000 \times 8 \times 2}{100} \) | 800 |
| 3 | 6 | 10 | 5000 | \( \frac{5000 \times 10 \times 6}{100} \) | 3000 |
| Total Simple Interest | 4400 | ||||
| Concept | Description | Formula |
|---|---|---|
| Principal | The initial amount of money invested or borrowed. | P |
| Simple Interest (SI) | Interest calculated only on the principal amount. | \( \text{SI} = \frac{P \times R \times T}{100} \) |
| Rate of Interest | The percentage at which interest is calculated per unit of time (usually per year). | R |
| Time | The duration for which the money is invested or borrowed. | T (in years, if rate is per annum) |
| Amount | The total sum after adding interest to the principal. | Amount = P + SI |
It's important to understand the difference between simple interest and compound interest, although this problem specifically uses simple interest.
In this problem, because it specifies "simple interest", we calculate the interest for each period independently based on the initial principal of Rs. 5,000, even though the rate changes.
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