Let the principal sum be denoted by \(P\). We need to find the value of \(P\).
The formula for simple interest (SI) is given by:
$ SI = \frac{P \times R \times T}{100} $
where \(P\) is the principal sum, \(R\) is the annual interest rate (in percentage), and \(T\) is the time period (in years).
For the first scenario:
The simple interest (\(SI_1\)) is:
$ SI_1 = \frac{P \times 8 \times 3}{100} = \frac{24P}{100} $
For the second scenario:
The simple interest (\(SI_2\)) is:
$ SI_2 = \frac{P \times 9 \times 2}{100} = \frac{18P}{100} $
The problem states that the simple interest in the first case (\(SI_1\)) is ₹96 more than the simple interest in the second case (\(SI_2\)). Therefore:
$ SI_1 - SI_2 = 96 $
Substitute the expressions for \(SI_1\) and \(SI_2\) into the equation:
$ \frac{24P}{100} - \frac{18P}{100} = 96 $
Combine the terms on the left side:
$ \frac{24P - 18P}{100} = 96 $
$ \frac{6P}{100} = 96 $
To solve for \(P\), multiply both sides by 100:
$ 6P = 96 \times 100 $
$ 6P = 9600 $
Now, divide by 6:
$ P = \frac{9600}{6} $
$ P = 1600 $
The principal sum is ₹1,600.
Anil lent a sum of Rs. 5,000 on simple interest for 10 years in such a way that the rate of interest is 6% per annum for the first 2 years, 8% per anmum for the next 2 years and 10% per annum beyond 4 years. How much interest (in Rs.) will he earn at the end of 10 years?
What will be the simple interest on a sum of Rs. 12000 at the rate of 15 percent per annum for three years ?
If in 13 years fixed sum doubles at simple interest, what will be the interest rate per year? (correct to two decimal places)
On simple interest a sum of Rs. 640 becomes Rs. 832 in 2 years. What will Rs. 860 become in 4 years at the same rate of simple interest?
A certain sum amounts to Rs. 81840 in 3 years and to Rs. 92400 in 5 years at x% p.a. under simple interest. If the rate of interest is becomes (x + 2)%, then in how many years will the same sum double itself?