The problem asks for the simple interest earned on a principal amount deposited for a specific period.
The deposit was made on 5 February 2024 and withdrawn on 6 April 2024. The year 2024 is a leap year.
Convert the time period to years:
$ T = \frac{61}{366} $ years (since 2024 is a leap year).
The formula for simple interest is:
$ SI = \frac{P \times R \times T}{100} $
Where:
Substitute the values into the formula:
$ SI = \frac{4000 \times 7.5 \times 61}{100 \times 366} $
Simplify the calculation:
$ SI = \frac{40 \times 7.5 \times 61}{366} $
$ SI = \frac{300 \times 61}{366} $
$ SI = \frac{18300}{366} $
$ SI = 50 $
The simple interest earned is ₹50.
Anil lent a sum of Rs. 5,000 on simple interest for 10 years in such a way that the rate of interest is 6% per annum for the first 2 years, 8% per anmum for the next 2 years and 10% per annum beyond 4 years. How much interest (in Rs.) will he earn at the end of 10 years?
What will be the simple interest on a sum of Rs. 12000 at the rate of 15 percent per annum for three years ?
If in 13 years fixed sum doubles at simple interest, what will be the interest rate per year? (correct to two decimal places)
On simple interest a sum of Rs. 640 becomes Rs. 832 in 2 years. What will Rs. 860 become in 4 years at the same rate of simple interest?
A certain sum amounts to Rs. 81840 in 3 years and to Rs. 92400 in 5 years at x% p.a. under simple interest. If the rate of interest is becomes (x + 2)%, then in how many years will the same sum double itself?