What is the value of (x + 2)2 − (x − 2)2 when x = 1?
8
Using the identity (a + b)2 − (a − b)2 = 4ab with a = x and b = 2, the expression = 8x.
At x = 1, value = 8 × 1 = 8. (Check: (1 + 2)2 − (1 − 2)2 = 9 − 1 = 8.)
Hence, the answer is 8.
If \(x + \dfrac{1}{x} = 17\), then the value of \(x^2 + \dfrac{1}{x^2}\) is:
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(2a + 3b + 4c)2 + (2a − 3b − 4c)2 − 8a2 − 18b2 −32c2
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