What is the sum of \(\frac{3}{8} + \frac{5}{12}\)?
\(\frac{19}{24}\)
To add the fractions \(\frac{3}{8}\) and \(\frac{5}{12}\), we first need to find a common denominator. The least common multiple (LCM) of 8 and 12 is 24. We then rewrite each fraction with the common denominator of 24:
\(\frac{3}{8} = \frac{3 \times 3}{8 \times 3} = \frac{9}{24}\)
\(\frac{5}{12} = \frac{5 \times 2}{12 \times 2} = \frac{10}{24}\)
Now we can add the fractions:
\(\frac{9}{24} + \frac{10}{24} = \frac{9 + 10}{24} = \frac{19}{24}\)
Therefore, the sum of \(\frac{3}{8}\) and \(\frac{5}{12}\) is \(\frac{19}{24}\).
5 \(\frac{3}{4}\) + x + 2 \(\frac{1}{2}\) = 10 \(\frac{1}{8}\) Find the value of x.
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
Number 0.232323 can be written in rational form as:
Solve: \(\frac{1}{2}\) [{-2(2 + 3)*20}/2]
Match the following.
Column I | Column II | ||
a. | Equivalent fraction of \(\frac{7}{12}\) is | i. | Proper fraction |
b. | Equivalent fraction of \(\frac{9}{15}\) is | ii. | Improper fraction |
c. | \(\frac{7}{11}\) is | iii. | \(\frac{21}{36}\) |
d. | \(\frac{19}{5}\) is | iv. | \(\frac{3}{5}\) |