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Question

\(4/5^{th}\) of a piece of cloth was used to make ribbons of length \(100\text{ cm}\). What was the length of the cloth at the beginning?

This question was previously asked in
RRB ALP 2018 CBT 2 Fitter Question Paper (21-Jan-2019) (Shift 3)
The correct answer is
$125\text{ cm}$

Finding Original Cloth Length

This problem asks for the initial length of a piece of cloth given that a specific fraction of it was used to create ribbons of a known total length. We need to reverse the process to find the original length.

Calculating Initial Length

Let the original length of the cloth be represented by '\(L\)'.

We are given that \(\frac{4}{5}\) of the cloth was used.

The length of the ribbons made from this portion is \(100 \text{ cm}\).

Therefore, we can set up the equation:

\(\frac{4}{5} \times L = 100 \text{ cm}\)

Solving for L

  1. To find the value of \(L\), we need to isolate it. First, multiply both sides of the equation by 5:

    \(4 \times L = 100 \text{ cm} \times 5\)

    \(4 \times L = 500 \text{ cm}\)

  2. Next, divide both sides by 4:

    \(L = \frac{500 \text{ cm}}{4}\)

    \(L = 125 \text{ cm}\)

The original length of the cloth was \(125 \text{ cm}\).

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Similar Questions

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  2. Select the option that is related to the third term in the same way as the second term is related to the first term.
    \(4/5 : 0.8 :: 5/8 : ?\)
  3. ₹ 150 of Amit's pocket money was spent on a pair of shoes and ₹ 75 on a watch. The total amount spent was three-fourth of his total pocket money. What was the amount received by Amit as pocket money?
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Important Questions from Fractions

  1. 5 \(\frac{3}{4}\) + x + 2  \(\frac{1}{2}\) = 10  \(\frac{1}{8}\) Find the value of x.

  2. Simplify the expression 441 ÷  \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)

  3. Number 0.232323 can be written in rational form as:

  4. Solve: \(\frac{1}{2}\)  [{-2(2 + 3)*20}/2]

  5. Match the following.

    Column I

    Column II

    a.

    Equivalent fraction of \(\frac{7}{12}\)  is  

    i.

    Proper fraction

    b.

    Equivalent fraction of  \(\frac{9}{15}\)  is

    ii.

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    c.

    \(\frac{7}{11}\)  is

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    d.

    \(\frac{19}{5}\)  is

    iv.

    \(\frac{3}{5}\)

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