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Question

\(4/5^{th}\) of a piece of cloth was used to make ribbons of length \(100\text{ cm}\). What was the length of the cloth at the beginning?

This question was previously asked in
RRB ALP 2018 CBT 2 Fitter Question Paper (21-Jan-2019) (Shift 3)
The correct answer is
$125\text{ cm}$

Finding Original Cloth Length

This problem asks for the initial length of a piece of cloth given that a specific fraction of it was used to create ribbons of a known total length. We need to reverse the process to find the original length.

Calculating Initial Length

Let the original length of the cloth be represented by '\(L\)'.

We are given that \(\frac{4}{5}\) of the cloth was used.

The length of the ribbons made from this portion is \(100 \text{ cm}\).

Therefore, we can set up the equation:

\(\frac{4}{5} \times L = 100 \text{ cm}\)

Solving for L

  1. To find the value of \(L\), we need to isolate it. First, multiply both sides of the equation by 5:

    \(4 \times L = 100 \text{ cm} \times 5\)

    \(4 \times L = 500 \text{ cm}\)

  2. Next, divide both sides by 4:

    \(L = \frac{500 \text{ cm}}{4}\)

    \(L = 125 \text{ cm}\)

The original length of the cloth was \(125 \text{ cm}\).

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Important Questions from Fractions

  1. If three-fifths of a number is 54, what is two-ninth of it?

  2. Sunila had \(9\frac{1}{4}\) kg of flour to make bread with. If the recipe says that she needs  \(1\frac{1}{8}\) kg to make one loaf of bread, how many loafs can she make? Estimate to the nearest whole number.

  3. The value of \(\frac{{11}}{5} - \left( {\frac{2}{3}of\frac{3}{5} - \frac{1}{5}} \right) + \left( {\frac{6}{5} \div \frac{4}{5}} \right)\) is:

  4. In his career, a tennis player won 5 matches lost 12 matches and had 3 matches as draw. The fraction of the match he lost in his career is:

  5. Simplify:

    \(62\div 5 - \left(\frac{8}{9}\times \frac{18}{7}\right)\times \frac{7}{5}+\frac{5}{4}\times \frac{16}{25}\)

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