What is the slope of the line \(7x + 4y = 8\)?
\(-\dfrac{7}{4}\)
Rewrite the equation in slope-intercept form \(y = mx + c\), where m is the slope.
\(7x + 4y = 8\)
\(4y = -7x + 8\)
\(y = -\dfrac{7}{4}x + 2\)
The coefficient of x is the slope, so the slope is \(-\dfrac{7}{4}\).
Shortcut: for the line \(ax + by + c = 0\), slope = \(-\dfrac{a}{b} = -\dfrac{7}{4}\).
Hence the answer is \(-\dfrac{7}{4}\).
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