Find the slope of the line perpendicular to \(y = \dfrac{1}{4}x + 7\).
−4
The given line is already in slope-intercept form \(y = mx + c\):
\(y = \dfrac{1}{4}x + 7 \implies m = \dfrac{1}{4}\)
The slope of any line perpendicular to it is the negative reciprocal:
\(m_{\perp} = -\dfrac{1}{m} = -\dfrac{1}{1/4} = -4\)
Hence the perpendicular slope is −4.
In a triangle PQR, the centroid is at G(1, 2). If the vertices P and Q are at (3, -1) and (-2, 4) respectively, what are the coordinates of vertex R?
If line passing through (3,-1) with slope 4; find y-intercept.
What is the reflection of the point (-1, 5) in the line x = 1?
What are the co-ordinates of the centroid of a triangle, whose vertices are A(1, -5), B(-4, 0) and C(3, -4)?
Slope of the line AB is 4/3. Co-ordinates of points A and B are (x, -5) and (2, -3) respectively. What is the value of x?
What is the slope of a line perpendicular to \(y = -3x + 7\)?
The graph of \(y = 4x - 5\) passes through which point?
Which line has slope −1 and passes through (2, 3)?
What is the slope of the line \(7x + 4y = 8\)?
Find the co-ordinates of the centroid of a triangle whose vertices are A(1, 4), B(7, 8) and C(10, 12).