What is the reflection of the point (6, -1) in the line y = 2?
(6, 5)
For reflection of a point \((x, y)\) in a horizontal line \(y = k\), the x-coordinate is unchanged and the y-coordinate becomes \(2k - y\).
With \((x, y) = (6, -1)\) and \(k = 2\):
\[y' = 2(2) - (-1) = 4 + 1 = 5\]
Therefore the reflection is (6, 5).
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Important Questions from Co-ordinate Geometry
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