What is the area (in sq. units) of the triangle formed by the graphs of the equations 2x + 5y - 12 = 0, x + y = 3 and y = 0?
3 unit2
This explanation demonstrates how to calculate the area of a triangle formed by the intersection of three specific lines:
2x + 5y - 12 = 0,
x + y = 3, and
y = 0. We need to find the area in square units.
The vertices of the triangle are the points where each pair of the given lines intersect. We will find these three intersection points.
x + y = 3 and y = 0To find the intersection point, substitute the value of y from the second equation into the first equation:
Substitute \( y = 0 \) into \( x + y = 3 \):
\( x + 0 = 3 \)
This simplifies to \( x = 3 \).
So, the first vertex is (3, 0).
2x + 5y - 12 = 0 and y = 0Similarly, substitute \( y = 0 \) into the equation \( 2x + 5y - 12 = 0 \):
\( 2x + 5(0) - 12 = 0 \)
This simplifies to \( 2x - 12 = 0 \).
Adding 12 to both sides gives \( 2x = 12 \).
Dividing by 2, we get \( x = 6 \).
So, the second vertex is (6, 0).
2x + 5y - 12 = 0 and x + y = 3We have a system of two linear equations:
2x + 5y - 12 = 0x + y = 3From the second equation, we can express x in terms of y: \( x = 3 - y \).
Now, substitute this expression for x into the first equation:
\( 2(3 - y) + 5y - 12 = 0 \)
Distribute the 2: \( 6 - 2y + 5y - 12 = 0 \)
Combine like terms: \( 3y - 6 = 0 \)
Add 6 to both sides: \( 3y = 6 \)
Divide by 3: \( y = 2 \).
Now, substitute the value of y back into the expression for x:
\( x = 3 - y \)
\( x = 3 - 2 \)
\( x = 1 \).
So, the third vertex is (1, 2).
We have found the three vertices of the triangle: (3, 0), (6, 0), and (1, 2).
Notice that two vertices, (3, 0) and (6, 0), lie on the x-axis (the line \( y = 0 \)). We can use the segment connecting these points as the base of the triangle.
The length of the base is the distance between the points (3, 0) and (6, 0).
\( \text{Base Length} = |x_2 - x_1| = |6 - 3| = 3 \) units.
The height of the triangle is the perpendicular distance from the third vertex (1, 2) to the line containing the base (the x-axis). This is simply the absolute value of the y-coordinate of the third vertex.
\( \text{Height} = |y_3| = |2| = 2 \) units.
The formula for the area of a triangle is:
$$ \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} $$
Substitute the calculated base and height:
$$ \text{Area} = \frac{1}{2} \times 3 \times 2 $$
$$ \text{Area} = \frac{1}{2} \times 6 $$
$$ \text{Area} = 3 $$
The area of the triangle is 3 square units.
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