What is the number of digits in 7 25 , 8 23 and 9 20 respectively? [Given log 10 2 = 0.301, log 10 3 = 0.477, log 10 7 = 0.845]
22, 21, 20
To find the number of digits in a large positive integer \(N\), we can use the concept of common logarithms (logarithms base 10). The number of digits in \(N\) is given by the formula:
Number of digits \(= \lfloor \log_{10} N \rfloor + 1\)
Here, \(\lfloor \log_{10} N \rfloor\) represents the characteristic of the common logarithm of \(N\), which is the greatest integer less than or equal to \(\log_{10} N\).
We need to find the number of digits in \(7^{25}\). Using the formula, we first calculate \(\log_{10}(7^{25})\).
Using the logarithm property \(\log_b (a^c) = c \log_b a\):
\(\log_{10}(7^{25}) = 25 \log_{10} 7\)
We are given \(\log_{10} 7 = 0.845\). Substituting this value:
\(\log_{10}(7^{25}) = 25 \times 0.845\)
\(\log_{10}(7^{25}) = 21.125\)
The characteristic of \(\log_{10}(7^{25})\) is the integer part, which is \(\lfloor 21.125 \rfloor = 21\).
The number of digits in \(7^{25}\) is the characteristic plus 1:
Number of digits in \(7^{25} = 21 + 1 = 22\).
We need to find the number of digits in \(8^{23}\). We first calculate \(\log_{10}(8^{23})\).
Since \(8 = 2^3\), we can write \(8^{23}\) as \((2^3)^{23} = 2^{3 \times 23} = 2^{69}\).
So, we need to find \(\log_{10}(2^{69})\). Using the logarithm property \(\log_b (a^c) = c \log_b a\):
\(\log_{10}(8^{23}) = \log_{10}(2^{69}) = 69 \log_{10} 2\)
We are given \(\log_{10} 2 = 0.301\). Substituting this value:
\(\log_{10}(8^{23}) = 69 \times 0.301\)
\(\log_{10}(8^{23}) = 20.769\)
The characteristic of \(\log_{10}(8^{23})\) is the integer part, which is \(\lfloor 20.769 \rfloor = 20\).
The number of digits in \(8^{23}\) is the characteristic plus 1:
Number of digits in \(8^{23} = 20 + 1 = 21\).
We need to find the number of digits in \(9^{20}\). We first calculate \(\log_{10}(9^{20})\).
Since \(9 = 3^2\), we can write \(9^{20}\) as \((3^2)^{20} = 3^{2 \times 20} = 3^{40}\).
So, we need to find \(\log_{10}(3^{40})\). Using the logarithm property \(\log_b (a^c) = c \log_b a\):
\(\log_{10}(9^{20}) = \log_{10}(3^{40}) = 40 \log_{10} 3\)
We are given \(\log_{10} 3 = 0.477\). Substituting this value:
\(\log_{10}(9^{20}) = 40 \times 0.477\)
\(\log_{10}(9^{20}) = 19.080\)
The characteristic of \(\log_{10}(9^{20})\) is the integer part, which is \(\lfloor 19.080 \rfloor = 19\).
The number of digits in \(9^{20}\) is the characteristic plus 1:
Number of digits in \(9^{20} = 19 + 1 = 20\).
Based on our calculations using logarithms:
| Number | Logarithm (base 10) | Characteristic (\(\lfloor \text{log}_{10} N \rfloor\)) | Number of Digits (Characteristic + 1) |
|---|---|---|---|
| \(7^{25}\) | \(21.125\) | \(21\) | \(22\) |
| \(8^{23}\) | \(20.769\) | \(20\) | \(21\) |
| \(9^{20}\) | \(19.080\) | \(19\) | \(20\) |
Thus, the number of digits in \(7^{25}\), \(8^{23}\), and \(9^{20}\) are 22, 21, and 20 respectively.
| Concept | Description |
|---|---|
| Common Logarithm | Logarithm with base 10, denoted as \(\log_{10} x\). |
| Characteristic | The integer part of the common logarithm of a number \(N\). For \(N \ge 1\), it is \(\lfloor \log_{10} N \rfloor\). |
| Number of Digits | For a positive integer \(N\), the number of digits is equal to its characteristic plus one (\(\lfloor \log_{10} N \rfloor + 1\)). |
| Logarithm Property | \(\log_b (a^c) = c \log_b a\) |
Logarithms are not just useful for finding the number of digits in large numbers. They have many applications in various fields:
The common logarithm (base 10) is particularly useful because our number system is base 10. This makes the characteristic directly related to the magnitude or number of digits of a number. The mantissa (the fractional part of the logarithm) helps determine the sequence of digits in the number.
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