This solution explores the continuity of the function $f(x) = [2x]$, where $[y]$ denotes the greatest integer function (or floor function). The greatest integer function gives the largest integer less than or equal to $y$. We need to determine at which of the given points the function $f(x)$ is continuous.
A function $f(x)$ is considered continuous at a specific point $x=a$ if it meets the following three essential criteria:
The fundamental property of the greatest integer function, $g(y) = [y]$, is that it experiences jumps (discontinuities) precisely at integer values of $y$. For any value $y$ that is not an integer, the function $[y]$ is continuous.
In our specific function, $f(x) = [2x]$, the input to the greatest integer function is $2x$. Consequently, $f(x)$ will exhibit discontinuities whenever the expression $2x$ results in an integer. If we set $2x = n$, where $n$ represents any integer, the points of discontinuity for $f(x)$ are found at $x = n/2$. This means the function $f(x) = [2x]$ is discontinuous at points such as ..., $-1$, $-0.5$, $0$, $0.5$, $1$, $1.5$, $2$, $2.5$, and so on.
Let's carefully check the continuity of $f(x) = [2x]$ at each of the points given in the options.
For the point $x=1$, we evaluate $2x = 2 \times 1 = 2$. Since $2$ is an integer, the greatest integer function $[2x]$ will be discontinuous at this point.
Because the left-hand limit ($1$) is not equal to the right-hand limit ($2$), the function $f(x) = [2x]$ is discontinuous at $x=1$.
At the point $x=0.5$, the expression inside the greatest integer function is $2x = 2 \times 0.5 = 1$. As $1$ is an integer, the function is expected to be discontinuous.
The left-hand limit ($0$) differs from the right-hand limit ($1$). Therefore, the function $f(x) = [2x]$ is discontinuous at $x=0.5$.
For the point $x=2.5$, we calculate $2x = 2 \times 2.5 = 5$. Since $5$ is an integer, the function $f(x) = [2x]$ is discontinuous here.
Since the left-hand limit ($4$) is not equal to the right-hand limit ($5$), the function $f(x) = [2x]$ is discontinuous at $x=2.5$.
Let's consider the point $x=1.25$. Here, the value inside the greatest integer function is $2x = 2 \times 1.25 = 2.5$. Crucially, $2.5$ is not an integer. According to the properties of the greatest integer function, $f(x) = [2x]$ should be continuous at points where the argument ($2x$) is not an integer.
As all three conditions for continuity are met at $x=1.25$, the function $f(x) = [2x]$ is indeed continuous at this point.
The function $f(x) = [2x]$ is discontinuous solely at points $x$ where $2x$ is an integer (i.e., where $x = n/2$ for any integer $n$). Conversely, it is continuous at all points where $2x$ is not an integer.
Our detailed checks confirmed:
Therefore, the function $f(x) = [2x]$ is continuous at $x=1.25$.
Solve for $x$: $log_3(x-2) + log_3(x+4) = 3$
Which of these statements about the floor and ceiling functions are correct?
Statement I : \(\left\lfloor {2x} \right\rfloor = \left\lfloor x \right\rfloor + \left\lfloor {x + (1/2)} \right\rfloor \) for all real number x
Statement II : \(\left\lceil {x + y} \right\rceil = \left\lceil x \right\rceil + \left\lceil y \right\rceil \) for all real numbers x and y
The number of real solutions of equation x 2 - 3 |x| + 2 = 0 is:
If ϕ is the Euler’s Totient function, then ϕ(92) is:
Consider the linear congruence 6 x ≡ 3 (mod 9). Then the incongruent solutions modulo 9 of this congruence are: