There are n zeros appearing immediately after the decimal point in the value of (0.2) 25 . It is given that the value of log 10 2 = 0.30103. The value of n is
17
The question asks for the number of zeros that appear immediately after the decimal point in the value of \((0.2)^{25}\). This type of problem is typically solved using logarithms, specifically the characteristic of the common logarithm (base 10) of the number.
The number of zeros immediately after the decimal point in a number \(N < 1\) is related to the characteristic of its common logarithm, \(\log_{10}(N)\). If the characteristic of \(\log_{10}(N)\) is \(-c\), where \(c\) is a positive integer, then the number of zeros immediately after the decimal point is \(c-1\).
Let's calculate the logarithm of the given number, \((0.2)^{25}\). We are given that \(\log_{10} 2 = 0.30103\).
We need to find \(\log_{10} ((0.2)^{25})\). Using the property of logarithms, \(\log a^b = b \log a\):
\[ \log_{10} ((0.2)^{25}) = 25 \times \log_{10} (0.2) \]Using another property of logarithms, \(\log (a/b) = \log a - \log b\):
\[ \log_{10} (0.2) = \log_{10} \left( \frac{2}{10} \right) = \log_{10} 2 - \log_{10} 10 \]We know that \(\log_{10} 10 = 1\) and we are given \(\log_{10} 2 = 0.30103\). Substituting these values:
\[ \log_{10} (0.2) = 0.30103 - 1 = -0.69897 \]Now substitute this back into the expression for \(\log_{10} ((0.2)^{25})\):
\[ \log_{10} ((0.2)^{25}) = 25 \times (-0.69897) \]
Let's perform the multiplication:
\[ 25 \times 0.69897 = 17.47425 \]
So, \(\log_{10} ((0.2)^{25}) = -17.47425\).
The value of \(\log_{10} ((0.2)^{25})\) is \(-17.47425\). We need to express this in the form Characteristic + Mantissa, where the mantissa is non-negative.
\[ -17.47425 = -18 + 0.52575 \]
In this expression, the characteristic is \(-18\) and the mantissa is \(0.52575\).
The characteristic of the logarithm is \(-18\). As discussed earlier, if the characteristic is \(-c\), the number of zeros immediately after the decimal point is \(c-1\).
Here, the characteristic is \(-18\), so \(c=18\). The number of zeros \(n\) is:
\[ n = c - 1 = 18 - 1 = 17 \]
Therefore, there are 17 zeros appearing immediately after the decimal point in the value of \((0.2)^{25}\).
| Step | Calculation | Result | Notes |
|---|---|---|---|
| 1 | \(\log_{10} (0.2) = \log_{10} 2 - \log_{10} 10\) | \(0.30103 - 1\) | Using \(\log(a/b)\) property |
| 2 | \(-0.69897\) | Value of \(\log_{10} (0.2)\) | |
| 3 | \(\log_{10} ((0.2)^{25}) = 25 \times \log_{10} (0.2)\) | \(25 \times (-0.69897)\) | Using \(\log a^b\) property |
| 4 | \(-17.47425\) | Value of \(\log_{10} ((0.2)^{25})\) | |
| 5 | Characteristic of \(-17.47425\) | \(-18\) | Integer part when mantissa is non-negative |
| 6 | Number of zeros \(n = |\text{Characteristic}| - 1\) | \(18 - 1\) | Applying the rule for zeros after decimal |
| 7 | \(17\) | Final number of zeros |
The value of \(n\), the number of zeros appearing immediately after the decimal point, is 17.
| Number \(N\) | \(\log_{10} N\) | Characteristic | Number of Zeros After Decimal |
|---|---|---|---|
| 0.5 | \(\approx -0.30103 = -1 + 0.69897\) | -1 | \(1 - 1 = 0\) (e.g., 0.5) |
| 0.05 | \(\approx -1.30103 = -2 + 0.69897\) | -2 | \(2 - 1 = 1\) (e.g., 0.05) |
| 0.005 | \(\approx -2.30103 = -3 + 0.69897\) | -3 | \(3 - 1 = 2\) (e.g., 0.005) |
| \(N < 1\) with characteristic \(-c\) | \(-c + \text{mantissa}\) (mantissa \(\ge 0\)) | \(-c\) | \(c - 1\) |
Logarithms are powerful tools for simplifying calculations involving multiplication, division, and exponents. The common logarithm (base 10) is particularly useful for determining the number of digits in a large number or the number of zeros after the decimal point in a small number.
The characteristic of \(\log_{10} N\) tells us about the magnitude of the number \(N\).
In our case, \(\log_{10} ((0.2)^{25}) = -17.47425\). The characteristic is \(-18\). This means the first non-zero digit in \((0.2)^{25}\) appears in the 18th decimal place, and there are \(18-1 = 17\) zeros immediately after the decimal point.
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