What is the minimum number to be subtracted from 6321, which makes it completely divisible by 14?
7
To make a number exactly divisible by 14, subtract its remainder on division by 14.
Divide: $6321 \div 14 = 451$ with $14 \times 451 = 6314$.
Remainder $= 6321 - 6314 = 7$, so 7 must be subtracted to get 6314, which is divisible by 14.
Hence, 7.
The remainder in the expression $27\frac{3}{4}$ is:
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2. S is always divisible by 9.
select the correct answer using the code given below:
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