What is the area (in cm 2) of an equilateral triangle of side 8 cm?
16√3
The problem asks us to find the area of an equilateral triangle when its side length is given. An equilateral triangle is a triangle where all three sides are equal in length, and all three angles are equal (each being 60 degrees).
The area of an equilateral triangle can be calculated using a specific formula that depends only on the length of its side. If the side length of the equilateral triangle is denoted by \(s\), the area \(A\) is given by the formula:
\[A = \frac{\sqrt{3}}{4} \times s^2\]
We are given that the side length of the equilateral triangle is 8 cm. Let's plug this value into the formula:
\[s = 8 \text{ cm}\]
Substitute \(s = 8\) into the area formula:
\[A = \frac{\sqrt{3}}{4} \times (8 \text{ cm})^2\]
First, calculate the square of the side length:
\[8^2 = 8 \times 8 = 64\]
Now substitute this back into the formula:
\[A = \frac{\sqrt{3}}{4} \times 64 \text{ cm}^2\]
Next, simplify the expression:
\[A = \sqrt{3} \times \frac{64}{4} \text{ cm}^2\]
Divide 64 by 4:
\[\frac{64}{4} = 16\]
So, the area of the equilateral triangle is:
\[A = 16\sqrt{3} \text{ cm}^2\]
Let's look at the given options and compare them with our calculated area:
Our calculated area, \(16\sqrt{3} \text{ cm}^2\), matches Option 4.
The area of the equilateral triangle with a side length of 8 cm is \(16\sqrt{3}\) cm2. This calculation used the standard formula for the area of an equilateral triangle based on its side length.
| Property | Formula (side = s) | Example (side = 8 cm) |
|---|---|---|
| Perimeter | \(P = 3s\) | \(P = 3 \times 8 = 24\) cm |
| Area | \(A = \frac{\sqrt{3}}{4}s^2\) | \(A = \frac{\sqrt{3}}{4} \times 8^2 = 16\sqrt{3}\) cm<sup>2</sup> |
| Height | \(h = \frac{\sqrt{3}}{2}s\) | \(h = \frac{\sqrt{3}}{2} \times 8 = 4\sqrt{3}\) cm |
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