Using the following sequence, determine which of the given options does not belong to the group.
4 % M
The problem asks us to identify which option among the given choices does not follow the pattern exhibited by the others, based on the provided sequence: R B 7 5 E % M 3 W 4 8 Q 9 # B 2 A $ M S.
To solve this, we need to examine each option and find a relationship between the elements presented in the option and their positions within the original sequence. Let's first list the elements in the sequence and their corresponding positions:
| Element | Position | Element | Position | Element | Position | Element | Position |
|---|---|---|---|---|---|---|---|
| R | 1 | % | 6 | W | 9 | # | 14 |
| B | 2 | M | 7 | 4 | 10 | B | 15 |
| 7 | 3 | 3 | 8 | 8 | 11 | 2 | 16 |
| 5 | 4 | Q | 12 | A | 17 | ||
| E | 5 | 9 | 13 | $ | 18 | ||
| M | 19 | ||||||
| S | 20 |
Now, let's look at each option and determine the positions of its elements in the original sequence:
Let's examine the positions for each option:
Let's analyze the parity (whether a number is even or odd) of these positions:
| Option | Position 1 | Parity | Position 2 | Parity | Position 3 | Parity | Parity Pattern |
|---|---|---|---|---|---|---|---|
| 1 (# % 4) | 14 | Even | 6 | Even | 10 | Even | Even, Even, Even |
| 2 (R E W) | 1 | Odd | 5 | Odd | 9 | Odd | Odd, Odd, Odd |
| 3 (4 % M) | 10 | Even | 6 | Even | 7 | Odd | Even, Even, Odd |
| 4 (3 Q 2) | 8 | Even | 12 | Even | 16 | Even | Even, Even, Even |
Observing the parity patterns:
It becomes clear that Options 1, 2, and 4 share a common pattern: the positions of the elements in the original sequence are all of the same parity (either all even or all odd). Option 1 and Option 4 have all even positions, while Option 2 has all odd positions. This suggests a group where position parity is consistent within the option.
Option 3 breaks this pattern because its elements are at positions 10 (Even), 6 (Even), and 7 (Odd). The parity is mixed.
Therefore, Option 3 does not belong to the group.
By examining the positions of the elements from the original sequence, we found that the pattern for the group is that all three elements in an option must come from positions that are either all even or all odd. Option 3 contains elements from positions 10, 6, and 7, which have mixed parity (Even, Even, Odd). The other options (1, 2, and 4) consist of elements whose positions are all of the same parity.
Thus, Option 3 is the one that does not follow the rule and does not belong to the group.
| Option | Elements | Positions in Sequence | Parity of Positions | Belongs to Group? |
|---|---|---|---|---|
| 1 | # % 4 | 14, 6, 10 | Even, Even, Even | Yes (All Even) |
| 2 | R E W | 1, 5, 9 | Odd, Odd, Odd | Yes (All Odd) |
| 3 | 4 % M | 10, 6, 7 | Even, Even, Odd | No (Mixed Parity) |
| 4 | 3 Q 2 | 8, 12, 16 | Even, Even, Even | Yes (All Even) |
Sequence-based reasoning questions are common in logical and abstract reasoning tests. They require you to find a hidden pattern or rule within a given sequence of numbers, letters, symbols, or a combination thereof. The pattern can relate to various aspects:
To solve these problems effectively, it's helpful to:
This particular problem demonstrated a pattern based on the parity of the element's position in the source sequence, which is a common technique used in such puzzles.
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