Solve the following: (-6)[40 ÷ {7 - (-3)}] = ?
Understanding the order of operations is crucial when solving mathematical expressions like $(-6)[40 \div \{7 - (-3)\}]$. We follow the BODMAS or PEMDAS rule, which dictates the sequence for performing operations:
Let's break down the given expression step by step:
The expression is: $(-6)[40 \div \{7 - (-3)\}]$
Step 1: Solve the innermost brackets/braces.
We have $\{7 - (-3)\}$ inside the braces. Subtracting a negative number is the same as adding its positive counterpart.
\(7 - (-3) = 7 + 3 = 10\)
Now the expression becomes: $(-6)[40 \div 10]$
Step 2: Solve the operation inside the square brackets.
We have $40 \div 10$ inside the square brackets.
\(40 \div 10 = 4\)
Now the expression becomes: $(-6)[4]$ or simply $(-6) \times 4$
Step 3: Perform the multiplication.
Finally, multiply $(-6)$ by $4$. When multiplying a negative number by a positive number, the result is negative.
\((-6) \times 4 = -24\)
So, the value of the expression $(-6)[40 \div \{7 - (-3)\}]$ is $-24$.
Let's compare our result with the given options:
| Option | Value | Matches Result? |
|---|---|---|
| 1 | 24 | No |
| 2 | 60 | No |
| 3 | -60 | No |
| 4 | -24 | Yes |
The calculated value, $-24$, matches option 4.
| Rule | Explanation | Example |
|---|---|---|
| Brackets/Parentheses | Solve operations inside grouping symbols first ((), {}, []). | \((7-3) = 4\) |
| Orders/Exponents | Solve powers, roots, etc. | \(2^3 = 8\) |
| Division & Multiplication | Perform division and multiplication from left to right. | \(10 \div 5 \times 2 = 2 \times 2 = 4\) |
| Addition & Subtraction | Perform addition and subtraction from left to right. | \(5 + 3 - 2 = 8 - 2 = 6\) |
When solving mathematical expressions involving integers, remember these rules for basic operations:
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