To solve this problem, we need to understand and apply De Morgan's Laws, which are fundamental rules in Boolean algebra used for simplifying expressions.

De Morgan's Laws state the following:

• \overline{(A . B)} = \overline{A} + \overline{B}
• \overline{(A + B)} = \overline{A} . \overline{B}

Given the expression: \overline{( P . Q . R )}

We apply De Morgan's first law, which is a generalization for any number of variables:

\overline{( P . Q . R )} = \overline{P} + \overline{Q} + \overline{R}

Let's break this down step-by-step:

1. According to De Morgan's Law, the negation of a conjunction (AND) is equivalent to the disjunction (OR) of the negations.
2. Thus, for three variables combined using AND, like P . Q . R, the negated form is the OR of the individual negated variables.
3. This simplification results in: \overline{P} + \overline{Q} + \overline{R}

Therefore, the equivalent expression for \overline{( P . Q . R )} using De Morgan’s law is \overline{P} + \overline{Q} + \overline{R}.

The correct answer is: \overline{P} + \overline{Q} + \overline{R}