This problem involves two trains of equal length moving in the same direction on parallel lines. We are given their speeds and the time it takes for the faster train to completely pass the slower train. We need to find the length of each train.
The speeds of the two trains are \(v_1 = 39\) km/h and \(v_2 = 21\) km/h. Since they are moving in the same direction, the relative speed (\(v_{rel}\)) is:
\( v_{rel} = v_1 - v_2 \)
\( v_{rel} = 39 \text{ km/h} - 21 \text{ km/h} = 18 \text{ km/h} \)
The time is given in seconds, so we need the speed in m/s. The conversion factor is \(\frac{5}{18}\) m/s per km/h.
\( v_{rel} \text{ (m/s)} = 18 \times \frac{5}{18} \)
\( v_{rel} = 5 \text{ m/s} \)
The faster train passes the slower train in \(t = 26\) seconds. The total distance (\(D\)) covered during this time is the product of the relative speed and the time.
\( D = v_{rel} \times t \)
\( D = 5 \text{ m/s} \times 26 \text{ s} \)
\( D = 130 \text{ meters} \)
Let the length of each train be \(L\). Since the trains have equal length, the total distance \(D\) is the sum of their lengths:
\( D = L + L = 2L \)
We know \(D = 130\) meters, so:
\( 2L = 130 \text{ meters} \)
\( L = \frac{130}{2} \)
\( L = 65 \text{ meters} \)
Therefore, the length of each train is 65 meters.
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