Two trains, A and B, start simultaneously from stations Delhi and Mumbai respectively towards each other on parallel tracks. After meeting, train A takes 16 hours to reach Mumbai, and train B takes 9 hours to reach Delhi. If train A's speed is 60 km/h, what is the length of train B (in meters), given that it crosses a pole in 18 seconds?
400
Using the property of trains meeting: if after meeting, train A takes \(t_A\) hours and train B takes \(t_B\) hours to reach their respective destinations, then \(\frac{v_A}{v_B} = \sqrt{\frac{t_B}{t_A}}\).
Here \(t_A = 16\) h, \(t_B = 9\) h, so \(\frac{v_A}{v_B} = \sqrt{\frac{9}{16}} = \frac{3}{4}\).
Given \(v_A = 60\) km/h: \(\frac{60}{v_B} = \frac{3}{4}\), so \(v_B = 80\) km/h.
Convert train B's speed to m/s: \(80 \times \frac{1000}{3600} = \frac{200}{9}\) m/s.
Train B crosses a pole in 18 seconds, so its length \(= \frac{200}{9} \times 18 = 400\) m.
Hence, the length of train B is 400 metres.
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