This problem requires finding the length of Train B. We are given the speeds of two trains (A and B) moving in opposite directions, the length of Train A, and the time they take to cross each other.
When two objects move towards each other (opposite directions), their relative speed is the sum of their individual speeds. This is the effective speed at which they cover the distance between them.
To use the formula Distance = Speed × Time, units must be consistent. Convert speeds from km/hr to m/s.
The conversion factor is: 1 km/hr = \(\frac{5}{18}\) m/s.
Since trains A and B are moving in opposite directions, their relative speed (\(S_{rel}\)) is:
\(S_{rel} = S_A + S_B\)
\(S_{rel} = \frac{55}{3} + \frac{50}{3} = \frac{105}{3} = 35 \text{ m/s}\)
The total distance (\(D\)) covered when two trains cross each other is the sum of their lengths (\(L_A + L_B\)). This distance equals relative speed multiplied by time.
\(D = S_{rel} \times T\)
\(D = 35 \text{ m/s} \times 10 \text{ s} = 350 \text{ m}\)
We know that the total distance is the sum of the lengths of the two trains:
\(D = L_A + L_B\)
Substitute the known values:
\(350 \text{ m} = 240 \text{ m} + L_B\)
Solve for \(L_B\):
\(L_B = 350 \text{ m} - 240 \text{ m}\)
\(L_B = 110 \text{ m}\)
The length of Train B is 110 meters.
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