Two resistors of 4Ω and 6Ω are connected in series. Their combined resistance is:
10Ω
When resistors are connected in series, the same current flows through each of them, and the equivalent resistance is simply the sum of the individual resistances: \(R_{eq} = R_1 + R_2\).
Substituting the given values, \(R_{eq} = 4\,\Omega + 6\,\Omega = 10\,\Omega\).
So the combined resistance of the two resistors connected in series is 10 ohms, which is always greater than either individual resistance in a series combination.
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