Two parallel plates separated by 4 mm have a potential difference of 80 V. Assuming a uniform electric field, what is the magnitude of the electric field between them?
20,000 V/m
For a uniform electric field between two parallel plates, the electric field magnitude is given by the potential difference divided by the separation between the plates:
\(E = \dfrac{V}{d}\)
Here, \(V = 80\ \text{V}\) and \(d = 4\ \text{mm} = 4\times10^{-3}\ \text{m}\), so:
\(E = \dfrac{80}{4\times10^{-3}} = 20{,}000\ \text{V/m}\)
The magnitude of the electric field between the plates is therefore 20,000 V/m.
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Important Questions from Current Electricity
- In a parallel combination of resistors, which of the following quantities remains the same across all the resistors?
- Which of the following statements is/are true for a domestic circuit?
(i) All the appliances are connected in parallel.
(ii) The live wire in the domestic circuit has green insulation on it.
(iii) A fuse connected to the circuit allows excessive current to pass through the appliances.
(iv) The neutral wire in the domestic circuits has black insulation on it. A science teacher asks students to measure the current through a bulb using an ammeter. What precaution must the students follow?
- Which characteristic of parallel circuits makes them advantageous over series circuits for connecting multiple electrical gadgets in a house?
- In a domestic electric circuit, the main purpose of a FUSE is ________.
