This problem involves calculating the total time taken to fill a tank when two pipes, A and B, operate simultaneously. Pipe A fills the tank in 20 minutes, and Pipe B fills it in 30 minutes.
First, determine the rate at which each pipe fills the tank.
When both pipes are opened together, their filling rates add up to find the combined rate.
Combined Rate = Rate of Pipe A + Rate of Pipe B
Combined Rate = \(\frac{1}{20} + \frac{1}{30}\)
To add these fractions, we find a common denominator, which is 60.
Combined Rate = \(\frac{3}{60} + \frac{2}{60}\)
Combined Rate = \(\frac{5}{60}\)
Simplifying the fraction gives the combined rate:
Combined Rate = \(\frac{1}{12}\) of the tank per minute.
The total time taken to fill the tank is the inverse of the combined filling rate.
Time = \(\frac{1}{\text{Combined Rate}}\)
Time = \(\frac{1}{\frac{1}{12}}\)
Time = 12 minutes.
Thus, when both pipes A and B are opened together, they will fill the tank in 12 minutes.
Two pipes A and B can independently fill a tank completely in 20 and 30 minutes respectively. If both the pipes are opened simultaneously, how much time will they take to fill the tank completely?
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