This problem involves calculating the net time taken to fill a cistern when one inlet (tap) and one outlet (pipe) are operating simultaneously. We determine the rate at which each device works and then find the combined rate.
When both the tap and the outlet pipe are open, the tap adds water, and the pipe removes water. The net rate of filling is the difference between the filling rate and the emptying rate.
To subtract these fractions, we find a common denominator, which is 45.
The time required to fill the cistern is the reciprocal of the net filling rate.
To express \( \frac{45}{4} \) hours in hours and minutes:
Two pipes A and B can independently fill a tank completely in 20 and 30 minutes respectively. If both the pipes are opened simultaneously, how much time will they take to fill the tank completely?
The compound interest on Rs. 64,000 for 3 years, compounded annually at 7.5% p.a. is
A water tank can be emptied in 40 minutes by a pipe of d 'diameter, so how long will it take for a 2d diameter pipe to be emptied?
Two pipes X and Y can fill an empty tank in 16 hours and 20 hours respectively. Pipe Z alone can empty the completely filled tank in 25 hours. Firstly both pipes X and Y are opened and after 6 hours pipe Z is also opened. What will be the total time (in hours) taken to completely fill the tank?
Pipe J can fill a tank in 48 hours and pipe K can fill the same tank in 72 hours. If both the pipes are opened alternately for one hour each and pipe K is opened for the first hour, then in how much time the tank will be full?